php - 特定の値で配列を並べ替えますか？

Question

これは、mysqlクエリからプッシュされた出力配列です。

この配列を並べ替えて、最初に親カテゴリ、次に子カテゴリが表示されるようにする必要があります。

次のような出力が必要です

PHPでこれを行うことはできますか？

score 1 · Accepted Answer

あなたが試すことができます

# Short Version of your Array
$oldList = Array(
    "0" => Array("CategoryID" => 7,"CategoryName" => "Test it","Parent" => 2),
    "1" => Array("CategoryID" => 8,"CategoryName" => "Test all","Parent" => 4),
    "2" => Array("CategoryID" => 4,"CategoryName" => "Test Image","Parent" => 0),
    "3" => Array("CategoryID" => 2,"CategoryName" => "Test Sub","Parent" => 1),
    "4" => Array("CategoryID" => 3,"CategoryName" => "Test Category","Parent" => 0),
    "5" => Array("CategoryID" => 1,"CategoryName" => "Test Category","Parent" => 0),
    "6" => Array("CategoryID" => 5,"CategoryName" => "Test Category","Parent" => 0),
    "7" => Array("CategoryID" => 6,"CategoryName" => "Test Remove","Parent" => 0)
);

echo "<pre>";
print_r(__group($oldList));

使用した機能

function __group($oldList)
{
    # Get Category Position
    $category = array_map(function($item) { return $item['CategoryID'];}  ,$oldList); 

    #Get Only Parent List and add to new list
    $newList = array_filter($oldList , function($item) {  return $item['Parent']  == 0 ; } );

    foreach($oldList as $key => $value)
    {
        if($value['Parent'] != 0) {
            # Mapt Chiled to parent using Parent ID & Category ID 
            $newList[array_search($value['Parent'],$category)]['child'][] = $value;
        }
    }
    return $newList ;
}

出力

Array
(
    [2] => Array
        (
            [CategoryID] => 4
            [CategoryName] => Test Image
            [Parent] => 0
            [child] => Array
                (
                    [0] => Array
                        (
                            [CategoryID] => 8
                            [CategoryName] => Test all
                            [Parent] => 4
                        )

                )

        )

    [4] => Array
        (
            [CategoryID] => 3
            [CategoryName] => Test Category
            [Parent] => 0
        )

    [5] => Array
        (
            [CategoryID] => 1
            [CategoryName] => Test Category
            [Parent] => 0
            [child] => Array
                (
                    [0] => Array
                        (
                            [CategoryID] => 2
                            [CategoryName] => Test Sub
                            [Parent] => 1
                        )

                )

        )

    [6] => Array
        (
            [CategoryID] => 5
            [CategoryName] => Test Category
            [Parent] => 0
        )

    [7] => Array
        (
            [CategoryID] => 6
            [CategoryName] => Test Remove
            [Parent] => 0
        )

    [3] => Array
        (
            [child] => Array
                (
                    [0] => Array
                        (
                            [CategoryID] => 7
                            [CategoryName] => Test it
                            [Parent] => 2
                        )

                )

        )

)

score 0 · Accepted Answer

これにより、必要に応じてエントリがグループ化されます。

function groupData($data) {
    $tree = array();
    $waiting = array();
    $index = array();
    foreach ($data as &$entry) {
        $index[$entry['CategoryID']] = &$entry;
        if (isset($waiting[$entry['CategoryID']])) {
            $entry['children'] = &$waiting[$entry['CategoryID']];
        } else {
            $entry['children'] = array();
        }
        if ($entry['Parent']) {
            if (isset($index[$entry['Parent']])) {
                $index[$entry['Parent']]['children'][] = &$entry;
            } else {
                if (!isset($waiting[$entry['Parent']])) {
                    $waiting[$entry['Parent']] = array();
                }
                $waiting[$entry['Parent']][] = &$entry;
            }
        } else {
            $tree[] = &$entry;
        }
    }
    return $tree;
}

'sort'属性で結果を並べ替える必要がある場合は、SQLクエリで名前などを使用するのが最適です。上記の関数はレコードの順序を変更しません。

score 0 · Accepted Answer

以下のコードを使用できます。これにより、配列がグループ化され、並べ替えキーに応じてすべての配列（ルート配列と子配列）が並べ替えられます。新しいグループ化/ソートされた配列を取得するには、この$ newArray = groupMe（$ originalArray）;を使用します。

function groupMe($array) {
    $returningArray = array();

    $mapCatIdCategory = array();
    //first pass create mapCatIdCategory
    foreach ($array as &$item) {
        $mapCatIdCategory[$item['CategoryId']] = &$item;
        $item['child'] = array();
    }

    //second pass is for setting child
    foreach ($array as &$item) {
        $parentId = $item['Parent'];
        if ($parentId == 0) {   //no parent category => add to root
            $returningArray[] = &$item;
        }
        else if (isset($mapCatIdCategory[$parentId])){ //not sure if data is always valid
            $mapCatIdCategory[$parentId]['child'][] = &$item; 
        }
    }

    //third pass sort root and all child array(recursively)
    recursiveSort($returningArray);

    return $returningArray;
}

function recursiveSort(&$array) {
    foreach ($array as &$item) {
        if (count($item['child']) >  1) { //empty or 1 elements arrays are already sorted
            recursiveSort($item['child']); //sort child
        }
    }

    usort($array, "cmpCategory"); //sort array by user comparasion function
}

function cmpCategory($a, $b) {
    if ($a['sort'] == $b['sort']) {
        return 0;
    }
    return ($a['sort'] < $b['sort']) ? -1 : 1;
}

php - 特定の値で配列を並べ替えますか？

3 に答える 3

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