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以下では、geoIのすべてのパターンをgrepしようとしています。私の質問は、geoIのさまざまな値をカウントとともにリストする方法です。

元：

GeoIs:"Paramount","sumthing else"
GeoIs:"undefined","sumthing else"
GeoIs:"undefined","sumthing else"
GeoIs:"178","sumthing else"
GeoIs:"178","sumthing else"
and many more
...
...

期待される結果：

GeoIs:"Paramount" 1
GeoIs:"undefined" 2
GeoIs:"178" 2

指図

zcat file.gz | grep -P '"geoIs":".*?.undefined*?"' | sort -u -T.|wc -l

編集1：

GEOISは次の文字列で見つかります

  012-10-02 09:32:45{"e":{"ec":100001,"st":1349170352455,"bd":"Mozilla%2F5.0%20(Windows%20NT%206.1)%20AppleWebKit%2F537.4%20(KHTMf01f02008592~rt%2366.657~rv%2366.228~as%2317~st%231349170293955~cat%231349170352431~sp%23as~c%2334~pat%231349128562942","smplCookie":"undefined","geoIPAddress":"122.107.154.58","geoCountry":"australia","geoCity":"Vermont","geoRegion":"Victoria","geoPostalCode":"undefined","geoLatitude":"undefined","geoLongitude":"undefined","geoMetro":"0","geoArea":"0","geoIs"}}
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2 に答える 2

3

度数分布表を返すには、

sort | uniq -c | sort -n

ご提供いただいたサンプルデータは、

zcat file.gz | cut -f1 -d, | sort | uniq -c | sort -n

zcat file.gz | grep -o '"searchstring":"[^"]*"'| sort | uniq -c | sort -n
于 2012-10-04T11:14:39.817 に答える
1

awkの代替：

awk -F, '{a[$1]++;}END{for(x in a)if(x)print x,a[x]}' file


kent$  echo 'GeoIsp:"Paramount","sumthing else"
GeoIsp:"undefined","sumthing else"
GeoIsp:"undefined","sumthing else"
GeoIsp:"178","sumthing else"
GeoIsp:"178","sumthing else"
'|awk -F, '{a[$1]++;}END{for(x in a)if(x)print x,a[x]}'
GeoIsp:"Paramount" 1
GeoIsp:"undefined" 2
GeoIsp:"178" 2
于 2012-10-04T11:28:45.043 に答える