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私がやろうとしているのは、ウィジェットを購入するのが初めてである限り、前日にSeries Xまたはウィジェットを購入したすべての顧客を見つけることです。Series A彼らが複数の適格なウィジェットを購入した場合、Series Xランクが付けられ、私はそれの記録のみを取り戻す必要があります。うまくいけば、それは理にかなっているので、ここにデータがあります

[customers]
c_id     cp_id
--------------
1        cp1
2        cp2
3        cp3
4        cp4
5        cp5
6        cp6
7        cp7
8        cp8
9        cp9
10       cp10

[widget_orders - c_id maps to c_id in customers]
c_id    w_sku   o_date
----------------------
1       w1      2012-10-10
2       w1      2012-10-10
2       w2      2012-10-10
3       w1      2012-10-10
3       w2      2012-10-10
4       w1      2012-10-10
4       w2      2012-10-10
5       w1      2012-10-10
5       w2      2012-10-10
6       w1      2012-10-10
6       w2      2012-10-10
7       w2      2012-10-10
8       w1      2012-10-10
9       w3      2012-10-10

[widgets - w_sku maps to w_sku in widget_orders]
w_sku   w_series
------------------
w1      Series A
w2      Series X
w3      Series C

[customer_data - c_id maps to c_id in customers]
cp_id   seriesA_fPurch  seriesX_fPurch
--------------------------------------
cp3     
cp4     2012-09-15
cp5                     2012-09-15
cp6     2012-09-15      2012-09-15
cp7                     2012-09-15  
cp8     2012-09-15

そして、これが（）の説明を無視して取り戻したいデータです

cp_id   series
--------------
cp1     Series A (bought series A and had NO prior purchase history)
cp2     Series X (bought both series, but X has rank - no purchase history)
cp3     Series X (bought both series, but X has rank - has purchase history recors albeit not for these)
cp4     Series X (bought both series, but X has rank - already had A history anyways)
cp5     Series A (bought both series, although X has rank they had previously bought series X)

次の人は結果に表示されません

cp6 - they had previously bought both series
cp7 - bought a series x, but had in the past
cp8 - bought a series a, but had in the past
cp9 - bought a widget in neither series
cp10 - didnt buy anything

それがすべて理にかなっていて、誰かがここで私を助けてくれることを願っています！

したがって、ロジックを要約し、おそらくもう少し明確に定義するために、ここでは、ステップのような方法で発生する必要があることを説明する方法を説明します。

1) Find all customers who have no matching records in the customer_data table
2) Find all customers who have a null value in either *purch column in the customer_data table
3) Combine these results together
4) Take the results and find the customers who made a purchase yesterday
5) Take the results and find the customers who purchased Series A or Series X
6) Take the results and do the following
    6a) If the purchase was Series A and they have a value for series A purch already drop them from results
    6b) If the purchase was Series X and they have a value for series X purch already drop them from results
7) Take the results and remove duplicate records based on the cp_id - Series X takes presedence over Series A
4

1 に答える 1

2

要件を完全に理解しているかどうかはわかりませんが、次のことを試してください。

SELECT cp_id, w_series
FROM (
SELECT rank() over (partition BY wo."c_id" ORDER BY decode(w."w_series",'Series X',1,'Series A',2)) rank,
       wo."c_id" c_id,
       c."cp_id" cp_id,
       w."w_series" w_series
FROM widget_orders wo JOIN widgets w ON wo."w_sku"=w."w_sku"
  JOIN customers c on c."c_id"=wo."c_id"
LEFT OUTER JOIN customer_data cd ON c."cp_id" = cd."cp_id"
WHERE  w."w_series" IN ('Series A', 'Series X')
  AND  trunc(wo."o_date") = trunc(sysdate)-1
  AND ( (cd."seriesA_fPurch" IS NULL AND w."w_series"='Series A')
     OR (cd."seriesX_fPurch" IS NULL AND w."w_series"='Series X'))
  )
WHERE rank = 1

これがフィドルです

説明：
ステップのような数字によると
-1）+ 2）レコードを持たない人も見つけてnullを入れるので、 LEFT OUTER JOIN+cd."seriesA_fPurch" IS NULL条件+条件で実行されます。 3）明らか... 4）条件 5） 6）条件7）レコードと条件 にランクを付けることによってcd."seriesX_fPurch" IS NULL

trunc(wo."o_date") = trunc(sysdate)-1
w."w_series" IN ('Series A', 'Series X')
(cd."seriesA_fPurch" IS NULL AND w."w_series"='Series A') OR (cd."seriesX_fPurch" IS NULL AND w."w_series"='Series X')
WHERE rank = 1

于 2012-10-11T21:27:09.480 に答える