0

文字列とデータベースから取得した特定の値を出力しようとしています。たとえば、Microsoft Server 2008 では、次のように実行されました。

SELECT 
'SELECT c.name COLLATE SQL_Latin1_General_CP1_CI_AS colName, o.name COLLATE SQL_Latin1_General_CP1_CI_AS tableName, '''
+ NAME + ''' db FROM ' + NAME 
+ '.sys.all_columns as c INNER JOIN ' + NAME 
+ 
'.sys.all_objects o ON c.object_id = o.object_id WHERE c.name like ''%password%'' AND type = ''U'' UNION'
  FROM SYS.DATABASES

以下を返します。

SELECT c.NAME COLLATE SQL_LATIN1_GENERAL_CP1_CI_AS colName, 
       o.NAME COLLATE SQL_LATIN1_GENERAL_CP1_CI_AS tableName, 
       'master'                                    db 
  FROM MASTER.SYS.ALL_COLUMNS AS c 
       INNER JOIN MASTER.SYS.ALL_OBJECTS o 
               ON c.OBJECT_ID = o.OBJECT_ID 
 WHERE c.NAME LIKE '%password%' 
       AND TYPE = 'U' 
UNION 
SELECT c.NAME COLLATE SQL_LATIN1_GENERAL_CP1_CI_AS colName, 
       o.NAME COLLATE SQL_LATIN1_GENERAL_CP1_CI_AS tableName, 
       'tempdb'                                    db 
  FROM TEMPDB.SYS.ALL_COLUMNS AS c 
       INNER JOIN TEMPDB.SYS.ALL_OBJECTS o 
               ON c.OBJECT_ID = o.OBJECT_ID 
 WHERE c.NAME LIKE '%password%' 
       AND TYPE = 'U' 
UNION

しかし、MySQL で同様のことを試すと、次のようになります。

 SELECT 
'SELECT c.name COLLATE SQL_Latin1_General_CP1_CI_AS colName, o.name COLLATE SQL_Latin1_General_CP1_CI_AS tableName, '''
+ DB + ''' db FROM ' + DB 
+ '.sys.all_columns as c INNER JOIN ' + DB 
+ 
'.sys.all_objects o ON c.object_id = o.object_id WHERE c.name like ''%password%'' AND type = ''U'' UNION'
  FROM DB

必要なレコードの空白行のみを返します。誰でも助けることができますか？

4

1 に答える 1

1

MySQL では、演算子concatの代わりに関数 inが必要です。+

SELECT concat(
'SELECT c.name COLLATE SQL_Latin1_General_CP1_CI_AS colName, o.name COLLATE SQL_Latin1_General_CP1_CI_AS tableName, '''
, DB , ''' db FROM ' , DB 
, '.sys.all_columns as c INNER JOIN ' , DB 
, 
'.sys.all_objects o ON c.object_id = o.object_id WHERE c.name like ''%password%'' AND type = ''U'' UNION'
)  FROM DB
于 2012-10-18T11:03:38.850 に答える