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アプリケーションの機能: Web サイトに Facebook ログインを実装しました。そして、Jsonを介して応答を得ているFacebookグラフAPIからユーザー情報を保存したいと思います。

私の問題: json 応答からいくつかの個別の値を出力できますが、配列内にネストされた値を出力できません。json 応答から子の値を出力するにはどうすればよいですか?

       *Please see my code below. There i am able to print users info like name and id.
         But unable to get the location of  user from json response.*

Json 出力:

        --responseBody---{"id":"100003645579131","name":"Ashutosh Singh","first_name":"Ashutosh","location":{"id":"106377336067638","name":"Bangalore, India"}}
        ---json---{"work":[{"position":{"id":"140001066034322","name":"Senior Inspector"},"location":{"id":"106377336067638","name":"Bangalore, India"},"name":"Ashutosh Singh","last_name":"Singh","gender":"male"}

上記の値を出力する私のコード:

String newUrl = "https://graph.facebook.com/me?access_token=" + accessToken;
            httpclient = new DefaultHttpClient();
            HttpGet httpget = new HttpGet(newUrl);
            System.out.println("Get info from facebook --> executing request: "+ httpget.getURI()); 
            ResponseHandler<String> responseHandler = new BasicResponseHandler();
            String responseBody = httpclient.execute(httpget, responseHandler);
               System.out.println("--responseBody---"+responseBody);
            json = (JSONObject) JSONSerializer.toJSON(responseBody);
            System.out.println("---json---"+json);
            facebookId = json.getString("id");//this values are printing fine
            String firstName = json.getString("first_name");//this values are printing fine
            String lastName = json.getString("last_name");//this values are printing fine

            String location=json.getJSONArray("location").toString(); //Unable to print information. Plz give help me. I want to print the location name from the json results.

            System.out.println("locale:"+location); //Unable to print

エラーメッセージ：

javax.servlet.ServletException: net.sf.json.JSONException: JSONObject["location"] is not a JSONArray.
            org.apache.struts.action.RequestProcessor.processException(RequestProcessor.java:520)
            org.apache.struts.action.RequestProcessor.processActionPerform(RequestProcessor.java:427)
            org.apache.struts.action.RequestProcessor.process(RequestProcessor.java:228)
            org.apache.struts.action.ActionServlet.process(ActionServlet.java:1913)
            org.apache.struts.action.ActionServlet.doGet(ActionServlet.java:449)
            javax.servlet.http.HttpServlet.service(HttpServlet.java:617)
            javax.servlet.http.HttpServlet.service(HttpServlet.java:717)
        root cause

        net.sf.json.JSONException: JSONObject["location"] is not a JSONArray.
            net.sf.json.JSONObject.getJSONArray(JSONObject.java:1793)
            com.ebhasin.bstalentscareers.action.SecurityServlet.getUserMailAddressFromJsonResponse(SecurityServlet.java:88)
            com.ebhasin.bstalentscareers.action.FacebookLoginAction.execute(FacebookLoginAction.java:45)
            org.apache.struts.action.RequestProcessor.processActionPerform(RequestProcessor.java:425)
            org.apache.struts.action.RequestProcessor.process(RequestProcessor.java:228)
            org.apache.struts.action.ActionServlet.process(ActionServlet.java:1913)
            org.apache.struts.action.ActionServlet.doGet(ActionServlet.java:449)
            javax.servlet.http.HttpServlet.service(HttpServlet.java:617)
            javax.servlet.http.HttpServlet.service(HttpServlet.java:717)
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1 に答える 1

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JSON からわかるように、location は JSON Array ではなく、JSON オブジェクトです。getJSONArray() を使用して取得しています。代わりに getJSONObject() を使用してください。

于 2012-10-19T09:55:02.090 に答える