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私はプロジェクト構成が与えられているプロジェクトに取り組んでいます

project-config.xml

 <bean id="awsCredentials" class="com.amazonaws.auth.BasicAWSCredentials">
        <constructor-arg
                value="${com.myorg.sparrow.s3EnvironmentConfiguration.S3EnvironmentConfigurator.dest.ProposalManager-accessKeyId}"/>
        <constructor-arg
                value="${com.myorg.sparrow.s3EnvironmentConfiguration.S3EnvironmentConfigurator.dest.ProposalManager-secretAccessKey}"/>
    </bean>

この値を渡すことができる場所からテスト構成を追加しています

test-config.xml

<?xml version="1.0" encoding="UTF-8"?>
<beans xmlns="http://www.springframework.org/schema/beans"
       xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
       xmlns:context="http://www.springframework.org/schema/context"
       xsi:schemaLocation="http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans.xsd   http://www.springframework.org/schema/context http://www.springframework.org/schema/context/spring-context.xsd">

    com.myorg.sparrow.s3EnvironmentConfiguration.S3EnvironmentConfigurator-destBucketName=bucketname
    com.myorg.sparrow.s3EnvironmentConfiguration.S3EnvironmentConfigurator.dest.ProposalManager-accessKeyId=accesskey
    com.myorg.sparrow.s3EnvironmentConfiguration.S3EnvironmentConfigurator.dest.ProposalManager-secretAccessKey=secretaccess key

    <bean id="spa-evaluation-factory" class="com.myorg.sparrow..business.DummySpaEvaluationFactory"/>
    <import resource="classpath:/com/myorg/sparrow/spa_adapter/project-config.xml"/>
</beans>

しかし、これはうまくいきません。どうやって

変数が定義されているtest-config.xml 

com.myorg.sparrow.s3EnvironmentConfiguration.S3EnvironmentConfigurator-destBucketName=bucketname
        com.myorg.sparrow.s3EnvironmentConfiguration.S3EnvironmentConfigurator.dest.ProposalManager-accessKeyId=accesskey
        com.myorg.sparrow.s3EnvironmentConfiguration.S3EnvironmentConfigurator.dest.ProposalManager-secretAccessKey=secretaccess key

の値の代用project-config.xml

<bean id="awsCredentials" class="com.amazonaws.auth.BasicAWSCredentials">
            <constructor-arg
                    value="${com.myorg.sparrow.s3EnvironmentConfiguration.S3EnvironmentConfigurator.dest.ProposalManager-accessKeyId}"/>
4

1 に答える 1

3

この方法で行うことができます。プレースホルダーは解決されるはずです。

<context:property-placeholder location="classpath*:META-INF/spring/test.properties" local-override="true" properties-ref="localProperties" ignore-resource-not-found="true"/>

<util:properties id="localProperties">
    <prop key="com.myorg.sparrow.s3EnvironmentConfiguration.S3EnvironmentConfigurator-destBucketName">bucketname</prop>     
    <prop key="com.myorg.sparrow.s3EnvironmentConfiguration.S3EnvironmentConfigurator.dest.ProposalManager-accessKeyId">accesskey</prop>        
    <prop key="com.myorg.sparrow.s3EnvironmentConfiguration.S3EnvironmentConfigurator.dest.ProposalManager-secretAccessKey">secretaccess key</prop>     
</util:properties>

もう 1 つの方法は、上記の test.properties ファイルにエントリを含めることです。

于 2012-10-23T22:07:25.173 に答える