php - mysqlでdistinctを選択し、distinctを数えます

Question

これは可能ですか?テーブルの列から個別の行を選択し、単一のクエリで個別のフィールドごとに繰り返される行を数えます

$sql = "SELECT DISTINCT location and COUNT(DISTINCT location) 
        FROM ".$db_name.".$table_name 
        ORDER BY location ASC 
        LIMIT ". $start_page.",". $recordPer_page."";

Answer 1

こんにちは、このクエリはあなたを助けます:

SQLFIDDLE の例

SELECT   `location`, COUNT(`location`) 
    FROM     tbl   
    GROUP BY `location`
    ORDER BY `location`

データ：

    ('Africa'),
    ('Viena'),
    ('Mexico'),
    ('Chicago'),
    ('Miami'),
    ('Chicago'),
    ('Viena'),
    ('London'),
    ('Viena');

結果：

| LOCATION | COUNT(`LOCATION`) |
--------------------------------
|   Africa |                 1 |
|  Chicago |                 2 |
|   London |                 1 |
|   Mexico |                 1 |
|    Miami |                 1 |
|    Viena |                 3 |

Answer 2

試す、

SELECT   `location`, COUNT(DISTINCT `location`) 
FROM     ....   
GROUP BY `Location`
ORDER BY ....
LIMIT    ....