アドレス帳から連絡先を取得して、iOS の連絡先アプリと同じインデックス付きリストを使用してテーブル ビューに表示しようとしています。LAST NAME で連絡先を並べ替えています。姓が空の場合、アプリがクラッシュします。これが私のコードです
- (void)getAddressBookDataForUpdateRequest:(BOOL)isUpdateRequest {
if (self.peopleArray == nil) {
NSMutableArray *temp = [[NSMutableArray alloc]init];
self.peopleArray = temp;
}
if (self.batchUserArray == nil) {
NSMutableArray *temp = [[NSMutableArray alloc]init];
self.batchUserArray = temp;
}
row = [[NSMutableDictionary alloc] init];
words = [[NSMutableArray alloc]init];
ABAddressBookRef addressBook=ABAddressBookCreate();
CFArrayRef cfPeople=ABAddressBookCopyArrayOfAllPeople(addressBook);
CFMutableArrayRef cfPeopleMutable=CFArrayCreateMutableCopy(kCFAllocatorDefault, CFArrayGetCount(cfPeople), cfPeople);
CFArraySortValues(cfPeopleMutable, CFRangeMake(0, CFArrayGetCount(cfPeopleMutable)), (CFComparatorFunction)ABPersonComparePeopleByName, (void *)ABPersonGetSortOrdering());
NSArray *tempPeople=(__bridge NSArray *)cfPeopleMutable;
APP_DELGATE.people = [NSArray arrayWithArray:tempPeople];
peopleCount = [APP_DELGATE.people count];
lastCharacter = @"A";
if (peopleCount >0) {
int noOfRec = 0;
for (int i=0; i<peopleCount; i++) {
ABRecordRef record = (__bridge ABRecordRef)[APP_DELGATE.people objectAtIndex:i];
// Convert ABRecordRef to UserContactInfo object
UserContactInfo *user = [self getUserContactInfoFromABRecordRef:record isForUpdate:isUpdateRequest];
if (user != nil) {
currentCharacter = [[user.lastName substringToIndex:1]uppercaseString];
NSLog(@"Last: %@ :: Current:- %@",lastCharacter,currentCharacter);
if ([currentCharacter isEqualToString:lastCharacter]) {
[words addObject:user];
}
else {
row = nil;
row = [[NSMutableDictionary alloc] init];
[row setValue:lastCharacter forKey:@"sectionTitle"];
[row setValue:words forKey:@"sectionRows"];
[self.peopleArray addObject:row];
[self.batchUserArray addObject:row];
NSDictionary *dic = [NSDictionary dictionaryWithObjectsAndKeys:[self.batchUserArray mutableCopy],BATCH_DONE_KEY,[NSNumber numberWithBool:isUpdateRequest],@"isUpdateRequest", nil];
[[NSNotificationCenter defaultCenter] postNotificationName:BATCH_DONE_NOTIFICATION object:self userInfo:dic];
[self.batchUserArray removeAllObjects];
words = nil;
words = [[NSMutableArray alloc]init];
[words addObject:user];
NSLog(@"ASCII Value of %@ = %d :: Last Char %@ = %d",currentCharacter,[currentCharacter characterAtIndex:0],lastCharacter,[lastCharacter characterAtIndex:0]);
int lastCharAsciiValue = [lastCharacter characterAtIndex:0];
int currentCharAsciiValue = [currentCharacter characterAtIndex:0];
while ((lastCharAsciiValue +1) < (currentCharAsciiValue)) {
row = nil;
row = [[NSMutableDictionary alloc] init];
lastCharAsciiValue ++;
lastCharacter = [NSString stringWithFormat:@"%c",lastCharAsciiValue];
[row setValue:lastCharacter forKey:@"sectionTitle"];
[row setValue:[[NSMutableArray alloc]init] forKey:@"sectionRows"];
[self.peopleArray addObject:row];
[self.batchUserArray addObject:row];
}
}
lastCharacter = currentCharacter;
noOfRec++;
}
}
// For last char "z"
row = nil;
row = [[NSMutableDictionary alloc] init];
[row setValue:lastCharacter forKey:@"sectionTitle"];
[row setValue:words forKey:@"sectionRows"];
[self.peopleArray addObject:row];
[self.batchUserArray addObject:row];
NSLog(@"total rec count=%d",self.peopleArray.count);
NSDictionary *dic = [NSDictionary dictionaryWithObjectsAndKeys:self.batchUserArray,BATCH_DONE_KEY,[NSNumber numberWithBool:isUpdateRequest],@"isUpdateRequest", nil];
[[NSNotificationCenter defaultCenter] postNotificationName:BATCH_DONE_NOTIFICATION object:self userInfo:dic];
[self.batchUserArray removeAllObjects];
[[NSNotificationCenter defaultCenter]postNotificationName:TASK_DONE_NOTIFICATION object:self];
APP_DELGATE.allUsersArray = self.peopleArray;
}
else {
[[NSNotificationCenter defaultCenter]postNotificationName:NO_CONTACTS_AVAILABLE_NOTIFICATION object:nil];
}
CFRelease(addressBook);
}
LAST NAME が EMPTY の場合、アプリがクラッシュします
if ([currentCharacter isEqualToString:lastCharacter]) {
[words addObject:user];
}
姓が空であるかどうかを確認し、インデックス付きリストの UNNAMED セクションに表示するにはどうすればよいですか。どんな種類の助けも大歓迎です。前もって感謝します