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このクエリ:

SELECT `subscribers`.`email_address`, `subscribers`.`first_name`, `subscribers`.`last_name`,
        GROUP_CONCAT( DISTINCT t1.value SEPARATOR '|' ) AS 'Colors', GROUP_CONCAT( DISTINCT t2.value SEPARATOR '|' ) AS 'Languages'
FROM `subscribers`
LEFT JOIN `subscribers_multivalued` AS `t1` ON subscribers.subscriber_id = t1.subscriber_id AND t1.field_id = 112
LEFT JOIN `subscribers_multivalued` AS `t2` ON subscribers.subscriber_id = t2.subscriber_id AND t2.field_id = 111
WHERE (list_id = 40) AND (state = 1)
GROUP BY `subscribers`.`email_address` , `subscribers`.`first_name` , `subscribers`.`last_name`

実行計画あり:

id  select_type     table   type    possible_keys   key     key_len     ref     rows    Extra
1   SIMPLE  subscribers     ref     FK_list_id,state_date_added     FK_list_id  4   const   1753610     Using where; Using filesort
1   SIMPLE  t1  ref     subscriber_fk,field_fk  subscriber_fk   4   chad0598_mailablel.subscribers.subscriber_id    1    
1   SIMPLE  t2  ref     subscriber_fk,field_fk  subscriber_fk   4   chad0598_mailablel.subscribers.subscriber_id    1

原因不明のエラー: 一般エラー: 3 エラー書き込みファイル '/tmp/MYzamaNT' (Errcode: 28) in mysql.

この groupy のように、subscriber_id insead で書き直しました。

SELECT `subscribers`.`email_address`, `subscribers`.`first_name`, `subscribers`.`last_name`,
        GROUP_CONCAT( DISTINCT t1.value SEPARATOR '|' ) AS 'Colors', GROUP_CONCAT( DISTINCT t2.value SEPARATOR '|' ) AS 'Languages'
FROM `subscribers`
LEFT JOIN `subscribers_multivalued` AS `t1` ON subscribers.subscriber_id = t1.subscriber_id AND t1.field_id = 112
LEFT JOIN `subscribers_multivalued` AS `t2` ON subscribers.subscriber_id = t2.subscriber_id AND t2.field_id = 111
WHERE (list_id = 40) AND (state = 1)
GROUP BY `subscribers`.`subscriber_id`

このクエリの計画はより優れています (filesort ではありません):

id  select_type     table   type    possible_keys   key     key_len     ref     rows    Extra
1   SIMPLE  subscribers     ref     FK_list_id,state_date_added     FK_list_id  4   const   1753610     Using where
1   SIMPLE  t1  ref     subscriber_fk,field_fk  subscriber_fk   4   chad0598_mailablel.subscribers.subscriber_id    1    
1   SIMPLE  t2  ref     subscriber_fk,field_fk  subscriber_fk   4   chad0598_mailablel.subscribers.subscriber_id    1

それはmysqlで動作するようで、以前のクエリよりもはるかに高速です。mysql で動作しますが、SQL 標準に準拠していないため、GROUP BY に存在しないフィールドのリストに集約されたフィールドがあってはなりません。クエリを最後のクエリと同じくらい高速にし、SQL に準拠させる方法はありますか?

私もこのように書き直そうとしました：

SELECT `subscribers`.`email_address`, `subscribers`.`first_name`, `subscribers`.`last_name`,
        t1.colors AS 'Colors', t2.languages AS 'Languages'
FROM `subscribers`
LEFT JOIN (SELECT subscriber_id, GROUP_CONCAT( DISTINCT value SEPARATOR '|' ) AS 'colors'
           FROM subscribers_multivalued
           WHERE field_id = 112
           GROUP BY subscriber_id)  t1 ON t1.subscriber_id = `subscribers`.`subscriber_id`
LEFT JOIN (SELECT subscriber_id, GROUP_CONCAT( DISTINCT value SEPARATOR '|' ) AS 'languages'
           FROM subscribers_multivalued
           WHERE field_id = 111
           GROUP BY subscriber_id)  t2 ON t2.subscriber_id = `subscribers`.`subscriber_id`

このクエリの計画はさらに悪いものです。

1   PRIMARY     subscribers     ALL     NULL    NULL    NULL    NULL    23358546     
1   PRIMARY     <derived2>  ALL     NULL    NULL    NULL    NULL    900000   
1   PRIMARY     <derived3>  ALL     NULL    NULL    NULL    NULL    900000   
3   DERIVED     subscribers_multivalued     ALL     field_fk    field_fk    4       20621115    Using filesort
2   DERIVED     subscribers_multivalued     ALL     field_fk    field_fk    4       20621115    Using filesort

データが返されるまで待ちきれませんでした。

4

1 に答える 1

2

私は速い方を維持します。このバリエーションをテスト/ベンチマークすることもできます。

SELECT s.email_address, 
       s.first_name, 
       s.last_name,
       COALESCE(t1.Colors, '') AS Colors,
       COALESCE(t2.Languages, '') AS Languages
FROM subscribers AS s
  LEFT JOIN 
    ( SELECT t1.subscriber_id, 
          GROUP_CONCAT( DISTINCT t1.value SEPARATOR '|' ) AS Colors
      FROM subscribers AS s
        JOIN subscribers_multivalued AS t1
          ON s.subscriber_id = t1.subscriber_id 
      WHERE t1.field_id = 112
        AND s.list_id = 40 
        AND s.state = 1
      GROUP BY t1.subscriber_id 
    ) AS t1
    ON s.subscriber_id = t1.subscriber_id 
  LEFT JOIN 
    ( SELECT t2.subscriber_id, 
             GROUP_CONCAT( DISTINCT t2.value SEPARATOR '|' ) AS Languages
      FROM subscribers AS s
        JOIN subscribers_multivalued AS t2
          ON s.subscriber_id = t2.subscriber_id 
      WHERE t2.field_id = 111
        AND s.list_id = 40 
        AND s.state = 1
      GROUP BY t2.subscriber_id 
    ) AS t2
    ON s.subscriber_id = t2.subscriber_id 
WHERE s.list_id = 40 
  AND s.state = 1 ;

(field_id, subscriber_id, value)がテーブル内で一意である場合はsubscribers_multivalued、2 つを削除することもできますDISTINCT。

速度と効率については、お持ちのインデックスを確認してください。これらは、あなたのバージョンとこのバージョンの両方に役立ちます:

  • テーブルで、またはいずれかsubscribersのインデックス(list_id, state, subscriber_id)(state, list_id, subscriber_id)

  • 表では、または (2 番目に良い)subscribers_multivaluedのインデックス。(field_id, subscriber_id, value)(field_id, subscriber_id)

于 2012-11-02T15:53:29.043 に答える