1

以下の記録があります。

Id    Date          MondayMorning  MondayEvening  TuesdayMorning TuesdayEvening and so on
1   2012-01-01          2               3               2              2
2   2012-01-02          2               2               2              2

mondaymorning と mondayevening の状態が同じではないため、レコード 1 を 2 つのレコードに分割します。状態が同じ場合は、何もしません。

私が期待する結果：

Id    Date          MondayMorning  MondayEvening  TuesdayMorning  TuesdayEvening
1   2012-01-01          2               NULL          2                 2
1   2012-01-01          NULL            3             NULL              NULL
2   2012-01-02          2               2             2                 2

他の日も異なる場合がありますのでご注意ください。

私はすでにクエリを持っていますが、いくつかの変更が必要です。SQL Fiddleのクエリを参照してください 。ここに表示される出力は、問題が発生した場合です。TuesdayEvening と MondayEvening については、2 を期待しています。

SQL Fiddle に関する情報は次のとおりです。

Declare @t Table(Id int identity,[Date] Datetime,MondayMorning Int,MondayEvening Int,TuesdayMorning Int,TuesdayEvening Int)
Insert Into @t Select '2012-01-01',0,2,0,2

SELECT id
    ,date
    ,MondayMorning
    ,(CASE WHEN MondayEvening <> MondayMorning THEN NULL ELSE MondayEvening END) AS MondayEvening
    ,TuesdayMorning
    ,(CASE WHEN TuesdayEvening <> TuesdayMorning THEN NULL ELSE TuesdayEvening END) AS TuesdayEvening
FROM @t 

UNION ALL 

SELECT id
    ,date
    ,NULL AS MondayMorning
    ,(CASE WHEN MondayEvening = MondayMorning THEN NULL ELSE MondayEvening END) AS MondayEvening
    ,NULL AS TuesdayMorning
    ,(CASE WHEN TuesdayEvening = TuesdayMorning THEN NULL ELSE TuesdayEvening END) AS TuesdayEvening
FROM @t
WHERE --MondayMorning <> MondayEvening
--OR TuesdayMorning <> TuesdayEvening
MondayMorning <> MondayEvening
AND (MondayMorning != 0 and MondayEvening != 0)
OR TuesdayMorning <> TuesdayEvening
AND (TuesdayEvening != 0 and TuesdayMorning != 0)
4

1 に答える 1

1

SQL Server 2008+、VALUESサブクエリをエレガントに構築するために使用します。

Declare @t Table(Id int identity,[Date] Datetime,MondayMorning Int,MondayEvening Int,TuesdayMorning Int,TuesdayEvening Int)
Insert Into @t Select '2012-01-01',0,2,3,2

     SELECT t.Id, t.[Date],
            Case when MondayMorning=v.state then MondayMorning end MondayMorning,
            Case when MondayEvening=v.state then MondayEvening end MondayEvening,
            Case when TuesdayMorning=v.state then TuesdayMorning end TuesdayMorning,
            Case when TuesdayEvening=v.state then TuesdayEvening end TuesdayEvening
       FROM @t t
CROSS APPLY (select distinct State
               from (values(MondayMorning),
                           (MondayEvening),
                           (TuesdayMorning),
                           (TuesdayEvening)) v(state)) v(state)

SQL Server 2005では、VALUES()派生テーブルをSELECT .. UNION ALLに置き換えます。例：

CROSS APPLY (select distinct State
               from (SELECT MondayMorning UNION ALL
                     SELECT MondayEvening UNION ALL
                     SELECT TuesdayMorning UNION ALL
                     SELECT TuesdayEvening) v(state)) v(state)
于 2012-11-04T22:52:57.540 に答える