私はこの構文を使用していますが、エラーが発生しなければうまく機能するはずです。
SELECT
e.user_key,
e.char_key,
CONVERT(VARCHAR,substring(e.char_data, 9, 16)) AS name,
p.CHAR_DATA
FROM
CHAR_DATA0 AS e
INNER JOIN
CHAR_DATA1 AS p ON e.CHAR_KEY = p.CHAR_KEY
WHERE
p.CHAR_DATA LIKE '%'+CAST(cast(reverse(CONVERT(BINARY, 9998)) as BINARY(2)) AS BINARY(2))+'%'
ORDER BY
char_key
私は助けが必要です。このコードを変更して機能させるにはどうすればよいですか?
CHAR_DATA
列のタイプBINARY(2000)
次のようなデータがあります:(selectを使用して取得)
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
検索しようとしているエントリが含まれている場合は、これらの行のどこかを検索する必要があります。
私が見つけようとしているのは、常に 2 バイトです。したがって、上記の構文で 0x0E27 を探しています。
これは機能する構文ですが、私がやりたいことではありません:
SELECT
CONVERT(INT,cast(reverse(substring(char_data, 37, 2)) as BINARY(2))) AS helm
FROM CHAR_DATA0
WHERE CHAR_KEY = 5
別のこれは、 nvarchar(MAX) を使用すると、検索しようとしているデータさえ含まない結果が得られることです。