ええと、Bo の言うとおりです…でも、私は退屈でした。あなたはこれを簡単な方法(入力を数値に変換し、1を追加してテキストに戻す)に抵抗があるように見えるので、文字を使用してみました。これが私が思いついたものです。恐ろしいですが、「うまくいくようです」。
; enter a number and add 1 - the hard way!
; nasm -f elf32 myprog.asm
; ld -o myprog myprog.o -melf_i386
global _start
; you may have these in an ".inc" file
sys_exit equ 1
sys_read equ 3
sys_write equ 4
stdin equ 0
stdout equ 1
stderr equ 2
LF equ 10
section .data
prompt db "Enter a number - not more than 10 digits - no nondigits.", LF
prompt_size equ $ - prompt
errmsg db "Idiot human! Follow instructions next time!", LF
errmsg_size equ $ - errmsg
section .bss
buffer resb 16
fakecarry resb 1
section .text
_start:
nop
mov eax, sys_write
mov ebx, stdout
mov ecx, prompt
mov edx, prompt_size
int 80h
mov eax, sys_read
mov ebx, stdin
mov ecx, buffer + 1 ; leave a space for an extra digit in front
mov edx, 11
int 80h
cmp byte [buffer + 1 + eax - 1], LF
jz goodinput
; pesky user has tried to overflow us!
; flush the buffer, yell at him, and kick him out!
sub esp, 4 ; temporary "buffer"
flush:
mov eax, sys_read
; ebx still okay
mov ecx, esp ; buffer is on the stack
mov edx, 1
int 80h
cmp byte [ecx], LF
jnz flush
add esp, 4 ; "free" our "buffer"
jmp errexit
goodinput:
lea esi, [buffer + eax - 1] ; end of input characters
mov byte [fakecarry], 1 ; only because we want to add 1
xor edx, edx ; count length as we go
next:
; check for valid decimal digit
mov al, [esi]
cmp al, '0'
jb errexit
cmp al, '9'
ja errexit
add al, [fakecarry] ; from previous digit, or first... to add 1
mov byte [fakecarry], 0 ; reset it for next time
cmp al, '9' ; still good digit?
jna nocarry
; fake a "carry" for next digit
mov byte [fakecarry], 1
mov al, '0'
cmp esi, buffer + 1
jnz nocarry
; if first digit entered, we're done
; save last digit and add one ('1') into the space we left
mov [esi], al
inc edx
dec esi
mov byte [esi], '1'
inc edx
dec esi
jmp done
nocarry:
mov [esi], al
inc edx
dec esi
cmp esi, buffer
jnz next
done:
inc edx
inc edx
mov ecx, esi ; should be either buffer + 1, or buffer
mov ebx, stdout
mov eax, sys_write
int 80h
xor eax, eax ; claim "no error"
exit:
mov ebx, eax
mov eax, sys_exit
int 80h
errexit:
mov edx, errmsg_size
mov ecx, errmsg
mov ebx, stderr
mov eax, sys_write
int 80h
mov ebx, -1
jmp exit
;-----------------------------
それはあなたが念頭に置いていたことですか?