-3
#include <stdio.h>
#include <string.h>

/* Function prototypes */
void wordLength ( char *word );
void wordConcat ( char *wordC1, char *wordC2);


int main (void)
{

    int choice;
    char word [20];
    char wordC1 [20];
    char wordC2 [20];


    printf( "Choose a function by enterting the corresponding number: \n"
        "1) Determine if words are identical\n"
        "2) Count number of words in sentence provided\n"
        "3) Enter two strings to be strung together\n"
        "4) Quit program\n" );
    scanf( "%d", &choice );
    flushall();

    while (choice >= 1 && choice < 4) 

{

        /* if statements for appropriate user prompt and calls function */
        if (choice == 1) 
        {
            /* gather user input */
        printf( "\nYou have chosen to determine word length.\n"
                "Please enter the word:\t");
            gets( word );

            /* call function to output string as well as the string length */
            wordLength( word );


        }

        else if (choice == 2)
        {
            printf( "\nYou have chosen to concatenate 2 words with a % symbol in between them.\n"
                "Please enter word 1:\t");

            gets( wordC1 );

            printf("Please enter word 2:\t");

            gets( wordC2 );                     

            /* call function to output string as well as the string length */
            wordLength( word );
    }
}
}
void wordLength( char *word )

{
    int length;

    printf( "\nThe string entered is:  %s\n\n", word);

    length = strlen (word);

    printf("The string length is: %d\n", length);

    return;
}

void wordConcat(char *wordC1, char *wordC2)

{
    char symbol = "\ 25";
    char result;
    printf( "\nThe first word entered is:  %s\n", wordC1);
    printf( "\nThe second word entered is:  %s\n", wordC2);

    result = strcat( wordC1, symbol, wordC2);

    printf("Output: %s\n", result);

    return;
}

プログラムの wordConcat 関数に 2 つの単語を入力するたびに、文字列出力は意味のないものになります :( すべてのポインターが正しい場所を指しているように見えます。何が間違っているのでしょうか?

4

1 に答える 1

1

choice == 2wordLength()code はの代わりに呼び出しwordConcat()ているため、word渡される変数は設定されていません。

于 2012-11-12T00:37:36.103 に答える