16 進数カラーを RGB カラーに変換したい。
次のコードを使用しました。
Me.BackColor = RGB("#000000")
ただし、次の例外がスローされます。
Argument not specified for parameter 'Green' of 'Public Function RGB(Red As Integer, Green As Integer, Blue As Integer) As Integer'
それを行う正しい方法は何ですか?
ColorTranslator による:
ColorTranslator.FromHtml("#003399")
他の方法:
Public Function ConvertToRbg(ByVal HexColor As String) As Color
Dim Red As String
Dim Green As String
Dim Blue As String
HexColor = Replace(HexColor, "#", "")
Red = Val("&H" & Mid(HexColor, 1, 2))
Green = Val("&H" & Mid(HexColor, 3, 2))
Blue = Val("&H" & Mid(HexColor, 5, 2))
Return Color.FromArgb(Red, Green, Blue)
End Function
また:
Public Shared Function HexToColor(ByVal hexColor As String) As Color
If hexColor.IndexOf("#"c) <> -1 Then
hexColor = hexColor.Replace("#", "")
End If
Dim red As Integer = 0
Dim green As Integer = 0
Dim blue As Integer = 0
If hexColor.Length = 6 Then
red = Integer.Parse(hexColor.Substring(0, 2), NumberStyles.AllowHexSpecifier)
green = Integer.Parse(hexColor.Substring(2, 2), NumberStyles.AllowHexSpecifier)
blue = Integer.Parse(hexColor.Substring(4, 2), NumberStyles.AllowHexSpecifier)
ElseIf hexColor.Length = 3 Then
red = Integer.Parse(hexColor(0).ToString() + hexColor(0).ToString(), NumberStyles.AllowHexSpecifier)
green = Integer.Parse(hexColor(1).ToString() + hexColor(1).ToString(), NumberStyles.AllowHexSpecifier)
blue = Integer.Parse(hexColor(2).ToString() + hexColor(2).ToString(), NumberStyles.AllowHexSpecifier)
End If
Return Color.FromArgb(red, green, blue)
End Function
また:
Dim c As String = "#ffffff"
c = Replace(c, "#", "")
c = "&H" & c
ColorTranslator.FromOle(c)
また:
Public Function hexToRbgNew(ByVal Hex As String) As Color
Hex = Replace(Hex, "#", "")
Dim red As String = "&H" & Hex.Substring(0, 2)
Hex = Replace(Hex, red, "", , 1)
Dim green As String = "&H" & Hex.Substring(0, 2)
Hex = Replace(Hex, green, "", , 1)
Dim blue As String = "&H" & Hex.Substring(0, 2)
Hex = Replace(Hex, blue, "", , 1)
Return Color.FromArgb(red, green, blue)
End Function