sql - 依存関係のあるデータベースのビューをプログラムで削除および作成するためのスクリプトを作成する

Question

私はこのトピックを見ただけです。私の質問とよく似ています。しかし、スクリプトの作成にサードパーティを使用したくありません。データベースのビューを依存関係の順序でプログラム的にドロップして作成するスクリプトを作成したいと考えています。どうすればそんなことができますか？

Answer 1

最後に、私の答えがこのようなものであることがわかりましたが、これはネストレベルが 1 つのビューのためだけのものであることに注意してください。それ以上ではありません！:

SELECT MIN(Row) AS Row, CreateCmd FROM ( 
SELECT Row_Number() OVER (ORDER BY S.Row) As Row, S.CreateCmd FROM ( 
SELECT 0 AS Row, RTRIM(ISNULL(smv.definition, ssmv.definition)) AS CreateCmd 
FROM sys.all_objects AS v 
LEFT OUTER JOIN sys.sql_modules AS smv ON smv.object_id = v.object_id 
LEFT OUTER JOIN sys.system_sql_modules AS ssmv ON ssmv.object_id = v.object_id 
INNER JOIN (SELECT object_id, referenced_major_id FROM sys.sql_dependencies 
GROUP BY object_id, referenced_major_id) AS a ON v.object_id = a.referenced_major_id
WHERE (v.type = 'V' OR v.type = 'P' OR v.type = 'IF' OR v.type = 'TF' OR v.type =    'FN') 
AND SCHEMA_NAME(v.schema_id) = N'dbo' AND is_ms_shipped <> 1 
AND smv.execute_as_principal_id IS NULL AND ssmv.execute_as_principal_id IS NULL 
GROUP BY v.Name, smv.definition, ssmv.definition 
UNION ALL 
SELECT 1 AS Row, RTRIM(ISNULL(smv.definition, ssmv.definition)) AS CreateCmd 
FROM sys.all_objects AS v 
LEFT OUTER JOIN sys.sql_modules AS smv ON smv.object_id = v.object_id 
LEFT OUTER JOIN sys.system_sql_modules AS ssmv ON ssmv.object_id = v.object_id 
INNER JOIN (SELECT object_id, referenced_major_id FROM sys.sql_dependencies 
GROUP BY object_id, referenced_major_id) AS a ON v.object_id = a.object_id
WHERE (v.type = 'V' OR v.type = 'P' OR v.type = 'IF' OR v.type = 'TF' OR v.type = 'FN') 
AND SCHEMA_NAME(v.schema_id) = N'dbo' AND is_ms_shipped <> 1 
AND smv.execute_as_principal_id IS NULL AND ssmv.execute_as_principal_id IS NULL 
GROUP BY v.Name, smv.definition, ssmv.definition 
) S GROUP BY S.Row, CreateCmd 
) D GROUP BY CreateCmd ORDER BY Row