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私はクエリを実行しています:

select 
    iars.id,students.rollno,
    students.name as name, 
    teachers.name as tname, 
    students.studentid, 
    t1.studentid,
    sum(t1.obt) as obt1, sum(t1.benefits) as ben1, sum(t1.max)  as max1,
    (t2.obt) as obt2, (t2.benefits) as ben2, (t2.max)  as max2,
    (t3.obt) as obt3, (t3.benefits) as ben3, (t3.max)  as max3,
    (t4.obt) as obt4, (t4.benefits) as ben4, (t4.max)  as max4,
    (t5.obt) as obt5, (t5.benefits) as ben5, (t5.max)  as max5 
from groups,students
left join iars on iars.id
left join str on str.studentid=students.studentid
left join course on course.c_id=students.course 
left join teachers on teachers.id=iars.teacherid
join sgm on sgm.studentid=students.studentid
left join semdef on month
left join sps on sps.studentid=students.studentid and iars.paperid=sps.paperid
left join `attndata` `t1` on ((t1.studentid=students.studentid) and iars.id=t1.iarsid and t1.mon=1)
left join `attndata` `t2` on ((t1.studentid=t2.studentid) and t2.mon = 2 and iars.id=t2.iarsid)
left join `attndata` `t3` on ((t2.studentid=t3.studentid) and t3.mon = 4 and iars.id=t3.iarsid)
left join `attndata` `t4` on ((t3.studentid=t4.studentid) and t4.mon = 5 and iars.id=t4.iarsid)
left join `attndata` `t5` on ((t4.studentid=t5.studentid) and t5.mon = 6 and iars.id=t5.iarsid)
where students.course='1' and students.status='regular' and sps.paperid='2' and 
iars.courseid=students.course and iars.semester=str.semesterid and iars.paperid='2' and
str.semesterid='1' and str.sessionid='12' and groups.id=sgm.groupid 
group by sps.studentid , teachers.id order by students.name

月ごとに合計したいのですが、合計を使用するたびに面白い結果が得られます。

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1 に答える 1

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月ごとの合計が必要な場合は、日付と月でグループ化する必要があります。学生と教師でグループ化すると、月に複数の行が得られ、面白い結果が得られます

于 2012-11-14T19:21:00.910 に答える