Excelで立方根を見つけるための解決策を探しています。このウェブサイトで以下のコードを見つけました。
http://www.mrexcel.com/forum/excel-questions/88804-solving-equations-excel.html
残念ながら、私にはうまくいきません - #VALUE! が表示されます。私がそれを実行したとき、私はVBAしか学んでいないので、うまくデバッグできませんでした。
Sub QUBIC(P As Double, Q As Double, R As Double, ROOT() As Double)
' Q U B I C - Solves a cubic equation of the form:
' y^3 + Py^2 + Qy + R = 0 for real roots.
' Inputs:
' P,Q,R Coefficients of polynomial.
' Outputs:
' ROOT 3-vector containing only real roots.
' NROOTS The number of roots found. The real roots
' found will be in the first elements of ROOT.
' Method: Closed form employing trigonometric and Cardan
' methods as appropriate.
' Note: To translate and equation of the form:
' O'y^3 + P'y^2 + Q'y + R' = 0 into the form above,
' simply divide thru by O', i.e. P = P'/O', Q = Q'/O',
' etc.
Dim Z(3) As Double
Dim p2 As Double
Dim RMS As Double
Dim A As Double
Dim B As Double
Dim nRoots As Integer
Dim DISCR As Double
Dim t1 As Double
Dim t2 As Double
Dim RATIO As Double
Dim SUM As Double
Dim DIF As Double
Dim AD3 As Double
Dim E0 As Double
Dim CPhi As Double
Dim PhiD3 As Double
Dim PD3 As Double
Const DEG120 = 2.09439510239319
Const Tolerance = 0.00001
Const Tol2 = 1E-20
' ... Translate equation into the form Z^3 + aZ + b = 0
p2 = P ^ 2
A = Q - p2 / 3
B = P * (2 * p2 - 9 * Q) / 27 + R
RMS = Sqr(A ^ 2 + B ^ 2)
If RMS < Tol2 Then
' ... Three equal roots
nRoots = 3
ReDim ROOT(0 To nRoots)
For i = 1 To 3
ROOT(i) = -P / 3
Next i
Exit Sub
End If
DISCR = (A / 3) ^ 3 + (B / 2) ^ 2
If DISCR > 0 Then
t1 = -B / 2
t2 = Sqr(DISCR)
If t1 = 0 Then
RATIO = 1
Else
RATIO = t2 / t1
End If
If Abs(RATIO) < Tolerance Then
' ... Three real roots, two (2 and 3) equal.
nRoots = 3
Z(1) = 2 * QBRT(t1)
Z(2) = QBRT(-t1)
Z(3) = Z(2)
Else
' ... One real root, two complex. Solve using Cardan formula.
nRoots = 1
SUM = t1 + t2
DIF = t1 - t2
Z(1) = QBRT(SUM) + QBRT(DIF)
End If
Else
' ... Three real unequal roots. Solve using trigonometric method.
nRoots = 3
AD3 = A / 3#
E0 = 2# * Sqr(-AD3)
CPhi = -B / (2# * Sqr(-AD3 ^ 3))
PhiD3 = Acos(CPhi) / 3#
Z(1) = E0 * Cos(PhiD3)
Z(2) = E0 * Cos(PhiD3 + DEG120)
Z(3) = E0 * Cos(PhiD3 - DEG120)
End If
' ... Now translate back to roots of original equation
PD3 = P / 3
ReDim ROOT(0 To nRoots)
For i = 1 To nRoots
ROOT(i) = Z(i) - PD3
Next i
End Sub
Function QBRT(X As Double) As Double
' Signed cube root function. Used by Qubic procedure.
QBRT = Abs(X) ^ (1 / 3) * Sgn(X)
End Function
誰でも修正方法を教えてください。実行できるようになります。ありがとう。
編集: これは、Excel で実行する方法です (Qubic をサブではなく関数に変更しました) セル A1:A3 には、それぞれ p、q、r が含まれます セル B1:B3 には Roots() が含まれます セル C1:C3 には、 Qubic の出力
A1:1 A2:1 A3:1
B1:0.1 B2:0.1 B3:0.1
C1: C2: C3: {=QUBIC(A1,A2,A3,B1:B3)}
追加: @assylias からの修正で動作するようになったので、別のシートから次のことを試しています。
Function ParamAlpha(p,q,r) as Double
Dim p as Double
Dim q as Double
Dim r as Double
p=-5
q=-2
r=24
Dim Alpha as Double
Dim AlphaVector() as Double
AlphaVector=QubicFunction(p,q,r)
Alpha=FindMinPositiveValue(AlphaVector)
End Function
Function FindMinPositiveValue(AlphaVector) As Double
Dim N As Integer, i As Integer
N = AlphaVector.Cells.Count
Dim Alpha() As Double
ReDim Alpha(N) As Double
For i = 1 To N
If AlphaVector(i) > 0 Then
Alpha(i) = AlphaVector(i)
Else
Alpha(i) = 100000000000#
End If
Next i
FindMinPositiveValue = Application.Min(Alpha)
End Function
Excel で =ParamAlpha(-5,-2,24) を呼び出すと、返されます#VALUE!