1

誰でもこの問題を解決するのを手伝ってもらえますか? これを照会しようとしましたが、エラーが発生し続けます。

MySQL コード:

SELECT * FROM
(

 SELECT BU.*, BD.BOOK_TITLE AS BOOK_TITLE, BD.BOOK_COMPANY AS COMPANY,
     BD.RETURN_DATE AS RETURN 
 FROM BOOK_USER BU
 INNER JOIN BOOKING_DETAIL BD ON (BU.USR_ID = BD.USR_ID)
                
UNION

 SELECT BU.*, "NEW REGISTERED" AS BOOK TITLE, 'RENT-A-BOOK' AS COMPANY,
     BU.REGISTER_DATE AS RETURN 
 FROM BOOK_USER BU

) AS BU 
GROUP BY BU.USR_ID

テーブル:

BOOK_USER

+---------+----------+---------------+
| USR_ID  | USR_NAME | REGISTER_DATE |
+---------+----------+---------------+
| 1       | john     | 2011-09-20    |
+---------+----------+--------------+
| 2       | jane     | 2011-12-05    |
+---------+----------+--------------+
| 3       | doe      | 2012-02-16    |
+---------+----------+--------------+
| 4       | mary      | 2012-02-02  |
+---------+----------+--------------+

BOOKING_DETAIL

+---------+----------+------------+-----------+--------------+
| BOOK_ID  | USR_ID |  BOOK_TITLE | COMPANY   | RETURN_DATE  |
+----------+--------+-------------+-----------+--------------+
| 1       | 1       | DEAR JOHN   |ABC PVT LMT| 2011-11-01   |
+---------+---------+-------------+-----------+--------------|
| 2       | 1       | LUCKY       |  DEF      | 2012-03-18   |
+---------+---------+-------------+-----------+--------------|
| 3       | 1       | THE RISE    | GHI       | 2012-06-12   |
+---------+---------+-------------+-----------+--------------|
| 4       | 2       | HELLO       |    TIMES  | 2012-01-11   |
+---------+---------+-------------+-----------+--------------|
| 5       | 2       | SHOPAHOLIC  |           | 2012-08-31   |
+---------+---------+-------------+-----------+--------------|
| 6       | 3       | LOST        |           | 2012-06-20   |
+---------+---------+-------------+-----------+--------------|

結果は、最新のRETURN_DATE と USR_ID でソートされたものを返す必要があります。

例えば：

  1. ジョン、ザ・ライズ、GHI、2012-06-12
  2. ジェーン、買い物中毒、レンタルブック、2012-08-31
  3. ドウ、LOST、RENT-A-BOOK、2012-06-20
  4. メアリー, 新規登録,レンタルブック , 2012-02-02
4

3 に答える 3

0

クエリには、各ユーザーの最新情報を取得するサブクエリが含まれています。 RETURN_DATE

SELECT  a.*, c.BOOK_TITLE, c.RETURN_DATE
FROM    book_user a
        INNER JOIN
        (
            SELECT usr_ID, MAX(return_DATE) maxDate
            FROM booking_detail
            GROUP BY usr_ID
        ) b ON  a.usr_ID = b.usr_ID
        INNER JOIN booking_detail c
            ON  b.usr_ID = c.usr_ID AND
                b.maxDate = c.return_DATE

アップデート

使用LEFT JOINしてCOALESCE

SELECT  a.USR_ID,
        a.USR_NAME, 
        COALESCE(c.BOOK_TITLE,'RENT-A-BOOK') BOOK_TITLE, 
        COALESCE(c.RETURN_DATE, a.REGISTER_DATE) RETURN_DATE
FROM    book_user a
        LEFT JOIN
        (
            SELECT usr_ID, MAX(return_DATE) maxDate
            FROM booking_detail
            GROUP BY usr_ID
        ) b ON  a.usr_ID = b.usr_ID
        LEFT JOIN booking_detail c
            ON  b.usr_ID = c.usr_ID AND
                b.maxDate = c.return_DATE
于 2012-11-21T09:24:35.267 に答える
0

それを試してください：

SELECT *
FROM (
    (
        SELECT BU.*, BD.BOOK_TITLE, BD.BOOK_COMPANY AS COMPANY,BD.RETURN_DATE AS RETURN FROM BOOK_USER BU INNER JOIN BOOKING_DETAIL BD ON (BU.USR_ID = BD.USR_ID)
    ) UNION ALL (
        SELECT BU.*, BD.BOOK_TITLE, 'RENT-A-BOOK' AS COMPANY,BD.RETURN_DATE AS RETURN FROM BOOK_USER BU INNER JOIN BOOKING_DETAIL BD ON (BU.USR_ID = BD.USR_ID)
    )
) BU
GROUP BY BU.USR_ID
于 2012-11-21T09:25:32.300 に答える
0

次のクエリを使用して出力を直接取得できます。クエリを確認してください。

SELECT BU.*, IFNULL(BD.BOOK_TITLE, 'NEW REGISTERED') AS BOOK_TITLE, IFNULL(BD.BOOK_COMPANY, 'RENT-A-BOOK') AS COMPANY,BD.RETURN_DATE AS RETURN 
FROM BOOK_USER BU
LEFT JOIN (SELECT * FROM (SELECT USR_ID, BOOK_TITLE, BOOK_COMPANY, RETURN_DATE FROM BOOKING_DETAIL ORDER BY RETURN_DATE DESC) AS A GROUP BY USR_ID) AS BD ON (BU.USR_ID = BD.USR_ID) 
ORDER BY BU.USR_ID;
于 2012-11-21T09:44:58.490 に答える