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私はC++プロジェクトのアドベンチャーゲームに取り組んでいます。目標は基本的に、クラスによって定義された部屋の束を持つことです。次に、マップを使用してそれらをすべてリンクします。部屋がないかどうかを確認し、空の部屋に入力が行われないようにすることを除いて、すべてが機能しています。たとえば、「そこには何もありません」と表示され、移動する方向についてユーザーに再度通知します。現在、ある方向にスペースがなく、その方向が選択されていると、プログラムがクラッシュします。現在、少なくとも有効な方向（北、南、東、または西）が入力されていることを確認するように設定していますが、その方向が使用可能かどうかはチェックされません。誰かがそれをする良い方法を知っていますか？

main.cpp

    #include <iostream>
    #include <string>
    #include <map>

    #include "room.h"

    using namespace std;

    int main()
    {
        /* ---------- Variable Declerations ---------- */
        string exitChoice;

        /* ---------- Room Intialization ---------- */
        room *kitchen = new room("Kitchen", "You are in the Kitchen. Pots and pans dangle above your head as you look across the room.");
        room *diningRoom = new room("Dining Room", "You are in the Dining Room. You see a large table in the center of the room complete with a set of chairs. It seems no one has ate here in quite som time.");
        room *garage = new room("Garage", "You are in the Garage. There are tools spread across the concerte floor complete with a Jeep Grand Cherokee on jack stands.");
        room *masterBed = new room("Master Bed Room", "You are in the Bed Room. A large Master Bed greets you as you walk into the room. You can see a large master bath as weel in the backround");
        room *hallway = new room("Hallway", "You are in the Hallway. A large set of stairs leads to the second floor, complete with a set to the basement. You also see a grand front door.");
        room *familyRoom = new room("Family Room", "You are in the Family Room. You see a dark leather couch in front of you as well as a brand new LCD TV. It aappears South Park is on TV.");
        room *bathRoom = new room("Bath Room", "You are in the Bath Room. A small room containing just a toilet is in front of you.");
        room *frontLawn = new room("Front Lawn", "You are in the Front Lawn. You are on a pathway and observe freshly cut grass as well as several trees scattered across the yard.");
        room *backLawn = new room("Back Lawn", "You are in the Back Lawn. You see 'Spot' running around chasing a tennis ball, as well as his dog house. A large wooden fence keeps him in the yard.");

        /* ----------Room Links---------- */

        /* Kitchen */
        kitchen->link(diningRoom, "North");
        kitchen->link(garage, "East");
        kitchen->link(masterBed, "South");
        kitchen->link(hallway, "West");

        /* Dining Room */
        diningRoom->link(kitchen, "South");
        diningRoom->link(familyRoom, "West");

        /* Master Bed Room */
        masterBed->link(kitchen, "North");
        masterBed->link(bathRoom, "West");

        /* Garage */
        garage->link(kitchen, "West");
        garage->link(backLawn, "East");

        /* Back Lawn */
        backLawn->link(garage, "West");

        /* Family Room */
        familyRoom->link(diningRoom, "East");
        familyRoom->link(hallway, "South");

        /* Hallway */
        hallway->link(familyRoom, "North");
        hallway->link(kitchen, "East");
        hallway->link(bathRoom, "South");
        hallway->link(frontLawn, "West");

        /* Front Lawn */
        frontLawn->link(hallway, "East");

        /* Bath Room */
        bathRoom->link(hallway, "North");
        bathRoom->link(masterBed, "East");

        /* ----------Gameplay---------- */
        room *currentRoom = kitchen;

        while (exitChoice != "quit")
        {
            currentRoom->printRoom();
            cout << endl;

            currentRoom->printLiked();

            cout << "Which exit? (Or 'quit'):";
            cin >> exitChoice;

            if(exitChoice != "quit" && exitChoice != "North" && exitChoice != "South" && exitChoice != "East" && exitChoice != "West")
            {
                cout << "Invalid Entry!" << endl;
                cout << "Which exit? (Or 'quit'):";
                cin >> exitChoice;
            }

            cout << "You move to the " << exitChoice << "..." << endl;
            currentRoom->getLinked(exitChoice);

            currentRoom = currentRoom->getLinked(exitChoice);
        }
    }

room.h

#ifndef ROOM_H
#define ROOM_H

using namespace std;

#include <string>
#include <iostream>
#include <map>

class room
{
    private:
        string name;
        string description;

    public:

    /* Constructor Prototypes */
    room(string, string);
    room(string);

    /* Get Name */
    string getName()
    {
        return name;
    }

    /* Get Description */
    string getDescription()
    {
        return description;
    }

    /* Print Room Information */
    void room :: printRoom()
    {
        cout << "--" << getName() << "--" << endl;
        cout << getDescription() << endl;
    }

    /* Map */
    map<string, room*> exits;

    /* Link Function*/
    void link(room *room, string direction)
    {
        exits[direction] = room;
    }

    /* Print Linked Rooms */
    void printLiked()
    {
        map<string, room*> :: iterator it;

        cout << endl;

        for(it = exits.begin(); it != exits.end(); ++it)
        {
            cout << "Exit: ";
            cout << it->first << " (" << it->second->getName() << ")" << endl;

        }

        cout << endl;
    }

    /* Get linked room */
    room* getLinked(string direction)
    {
        map<string, room*> :: iterator it;

        it = exits.find(direction);

        if(it != exits.end())
        {
            return it->second;
        }
        else
        {
            return NULL;
        }


    }





};

#endif

room.cpp

 #include <iostream>
    #include <string>
    #include <map>

    using namespace std;

    #include "room.h"

        /* Constructor with Name and Description */
        room :: room(string _name, string _description)
        {
            name = _name;
            description = _description;
        }


        /* Contrsuctor with Name */
        room :: room(string _name)
        {
            name = _name;
        }

新しいmain.cppsnipet

        room* possibleNewRoom = currentRoom->getLinked(exitChoice);

        if (possibleNewRoom != 0)
        {
            currentRoom = possibleNewRoom;

            cout << "You move to the " << exitChoice << "..." << endl;
            currentRoom->getLinked(exitChoice);

            currentRoom = currentRoom->getLinked(exitChoice);
        }
        else
        {
            cout << "There are no exits in that direction." << endl;
        }
4

2 に答える 2

1

必要なもの：

room* possibleNewRoom = currentRoom->getLinked(exitChoice);

if (possibleNewRoom != 0)
{
    currentRoom = possibleNewRoom;
}
else
{
    std::cout << "Ouch - you cannot move that way" << std::endl;
}
于 2012-11-22T04:14:33.217 に答える
0

これを行う最も一般的な方法は、方向性のあるメンバーをRoomクラスに導入することです。

class Room {
    // ...
    Room *north, *south, *east, *west;
    // ...
    Room() : north(NULL), south(NULL), east(NULL), west(NULL)
    { /* ... */ }
};

次に、次のように部屋を相互に接続します。

Room* kitchen = new Room // ...
Room* hallway = new Room // ...
kitchen->north = hallway;
hallway->south = kitchen;

ある方向に移動しようとすると、その方向のメンバーが次のようになっているかどうかを確認するだけですNULL。

// Player wants to go north.
if (this->north == NULL) {
    // Tell the player that's not possible.
} else {
    // OK, we can go to this->north.
}

この設定により、より高度な接続を設定できます。たとえば、北に行ってから南に行くと、最初の場所に移動するべきではない場合（おそらく、魔法のポータルか、それらの線の中にあるものです）。

TADS（Text Adventure Development System）を見ると、これを設計する方法についていくつかの設計アイデアを得ることができます。

于 2012-11-22T04:20:25.303 に答える