1

次の 2 つの SELECT ステートメントを組み合わせて、2 番目のステートメントの結果が最初の選択のすべての行の列として表示されるようにする必要があります。

SELECT MEM.Id,
   EN.artistName,
   EN.dateAdded,
   EN.voteStatus,
   ES.enterNextRound,
   ES.notified,
   ES.voted,
   GR.genre,
   ES.entrantId AS bandID
FROM recMembers AS MEM
LEFT JOIN recEntrantStatus AS ES
   ON MEM.Id = ES.judgeId
LEFT JOIN recEntrants AS EN
   ON ES.entrantId = EN.Id
LEFT JOIN recGenre AS GR
   ON EN.genreId = GR.Id
WHERE MEM.Id = @memberId
   AND ES.roundId = 2

SELECT COUNT(enterNextRound) 
FROM recEntrantStatus
WHERE enterNextRound = 1
  AND roundId = 2
  AND entrantId = ES.entrantId

「ES.entrantId」は、最初の選択でアクセスされた現在の行から取得されます。

任意のポインタをいただければ幸いです。

ありがとう

4

3 に答える 3

3

あなたが使用することができますOUTER APPLY：

SELECT MEM.Id, 
  EN.artistName, 
  EN.dateAdded, 
  EN.voteStatus, 
  ES.enterNextRound,
  ES.notified, 
  ES.voted, 
  GR.genre, 
  ES.entrantId AS bandID, 
  src.CountEnterNextRound
FROM recMembers AS MEM
LEFT JOIN recEntrantStatus AS ES
  ON MEM.Id = ES.judgeId
LEFT JOIN recEntrants AS EN
  ON ES.entrantId = EN.Id
LEFT JOIN recGenre AS GR
  ON EN.genreId = GR.Id
OUTER APPLY
(
  SELECT COUNT(enterNextRound) CountEnterNextRound
  FROM recEntrantStatus
  WHERE enterNextRound = 1
    AND roundId = 2
    AND entrantId = @memberId
) src
WHERE MEM.Id = @memberId
  AND ES.roundId = 2

編集内容に基づいて、次のことを試しましたか。

SELECT MEM.Id,
   EN.artistName,
   EN.dateAdded,
   EN.voteStatus,
   ES.enterNextRound,
   ES.notified,
   ES.voted,
   GR.genre,
   ES.entrantId AS bandID,
   (SELECT COUNT(enterNextRound) 
    FROM recEntrantStatus
    WHERE enterNextRound = 1
      AND roundId = 2
      AND entrantId = ES.entrantId) CountEnterNextRound
FROM recMembers AS MEM
LEFT JOIN recEntrantStatus AS ES
   ON MEM.Id = ES.judgeId
LEFT JOIN recEntrants AS EN
   ON ES.entrantId = EN.Id
LEFT JOIN recGenre AS GR
   ON EN.genreId = GR.Id
WHERE MEM.Id = @memberId
   AND ES.roundId = 2

あるいは：

SELECT MEM.Id,
   EN.artistName,
   EN.dateAdded,
   EN.voteStatus,
   ES.enterNextRound,
   ES.notified,
   ES.voted,
   GR.genre,
   ES.entrantId AS bandID,
   src.CountEnterNextRound
FROM recMembers AS MEM
LEFT JOIN recEntrantStatus AS ES
   ON MEM.Id = ES.judgeId
LEFT JOIN recEntrants AS EN
   ON ES.entrantId = EN.Id
LEFT JOIN recGenre AS GR
   ON EN.genreId = GR.Id
LEFT JOIN
(
  SELECT COUNT(enterNextRound) CountEnterNextRound, entrantId
  FROM recEntrantStatus
  WHERE enterNextRound = 1
      AND roundId = 2
  GROUP BY entrantId
) src
  ON ES.entrantId = src.entrantId
WHERE MEM.Id = @memberId
   AND ES.roundId = 2;
于 2012-11-23T15:58:21.340 に答える
3

それをサブクエリでラップして使用しますCROSS JOIN

SELECT MEM.Id,
        EN.artistName,
        EN.dateAdded,
        EN.voteStatus,
        ES.enterNextRound,
        ES.notified,
        ES.voted,
        GR.genre,
        ES.entrantId AS bandID,
        s.totalCount
FROM recMembers AS MEM
        LEFT JOIN recEntrantStatus AS ES
                ON MEM.Id = ES.judgeId
        LEFT JOIN recEntrants AS EN
                ON ES.entrantId = EN.Id
        LEFT JOIN recGenre AS GR
                ON EN.genreId = GR.Id
        CROSS JOIN (
                SELECT COUNT(enterNextRound) totalCount
                FROM recEntrantStatus
                WHERE enterNextRound = 1
                        AND roundId = 2
                        AND entrantId = @memberId
                ) s
WHERE MEM.Id = @memberId
        AND ES.roundId = 2
于 2012-11-23T15:57:02.037 に答える
1

どうですか

SELECT * 
FROM
(
    SELECT MEM.Id, EN.artistName, EN.dateAdded, EN.voteStatus, ES.enterNextRound,
    ES.notified, ES.voted, GR.genre, ES.entrantId AS bandID
    FROM recMembers AS MEM
    LEFT JOIN recEntrantStatus AS ES
    ON MEM.Id = ES.judgeId
    LEFT JOIN recEntrants AS EN
    ON ES.entrantId = EN.Id
    LEFT JOIN recGenre AS GR
    ON EN.genreId = GR.Id
    WHERE MEM.Id = @memberId
    AND ES.roundId = 2
) x
,
(
    SELECT COUNT(enterNextRound) as Total
    FROM recEntrantStatus
    WHERE enterNextRound = 1
    AND roundId = 2
    AND entrantId = @memberId
) y

結合なしで FROM 2 テーブルを実行すると、クロス結合のようなデカルト積が得られます。したがって、同じ実行時間になるはずです。

これはそれを書くための暗黙の方法です。

于 2012-11-23T15:57:18.653 に答える