Web サービスを呼び出すための単純なクラスを作成しました
public class CallSoap {
public final String SOAP_ACTION = "http://tempuri.org/Add";
public final String OPERATION_NAME = "Add";
public final String WSDL_TARGET_NAMESPACE = "http://tempuri.org/";
public final String SOAP_ADDRESS = "http://localhost:41614/Service1.asmx";
public CallSoap()
{
}
public String Call(int a,int b)
{
SoapObject request = new SoapObject(WSDL_TARGET_NAMESPACE,OPERATION_NAME);
request.addProperty("a",a);
request.addProperty("b",b);
SoapSerializationEnvelope envelope = new SoapSerializationEnvelope(SoapEnvelope.VER11);
envelope.dotNet = true;
envelope.setOutputSoapObject(request);
HttpTransport httpTransport = new HttpTransport(SOAP_ADDRESS);
Object response=null;
try
{
httpTransport.call(SOAP_ACTION, envelope);
response = envelope.getResponse();
}
catch (Exception exception)
{
response=exception.toString();
}
return response.toString();
}
}
これが私のActivity
クリック方法です
public void clickData(View v)
{
//Intent intent = new Intent(this, DisplayMessageActivity.class);
EditText et=(EditText) findViewById(R.id.editText1);
EditText et2=(EditText) findViewById(R.id.editText2);
TextView tv=(TextView) findViewById(R.id.textView1);
int a=Integer.parseInt(et.getText().toString());
int b=Integer.parseInt(et2.getText().toString());
CallSoap cs=new CallSoap();
tv.setText(cs.Call(a, b));
}
「残念ながら App1 が停止しました」というエラーが表示されます。私を助けてください..