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簡単にするために、カテゴリ、サブカテゴリ、日付の 3 つの列のテーブル「タブ」として参照する結果セットがあり、カテゴリと日付の順に並べられています。このデータセットはグリッドであり、そのグリッドの上で他の処理を実行したいと考えています。私の問題は、データセット内のグループを一意に識別する (または順番にラベル付けする) ことです。以下の SQL は、最初の 3 つの列の存在に基づいて、私が求めているものです (GID1 または GID2 のいずれか)。group_id、grouping_id、rank、dense_rank を試みましたが、これらのいずれかでトリックを逃したか、非常に厄介なことを試みています。GID の順序は重要ではありませんが、グループ番号の割り当てがデータの順序 (カテゴリ、次に日付) に基づいていることが重要です。

 CREATE TABLE Tab
        ("Category" varchar2(1), "SubCategory" varchar2(7), "Date" int, "GID1" int, "GID2" int);

    INSERT ALL 
        INTO Tab ("Category", "SubCategory", "Date", "GID1", "GID2")
             VALUES ('A', 'bannana', 20120101, NULL, NULL)
        INTO Tab ("Category", "SubCategory", "Date", "GID1", "GID2")
             VALUES ('A', 'grape', 20120102, NULL, NULL)
        INTO Tab ("Category", "SubCategory", "Date", "GID1", "GID2")
             VALUES ('A', 'pear', 20120103, 1, 1)
        INTO Tab ("Category", "SubCategory", "Date", "GID1", "GID2")
             VALUES ('A', 'pear', 20120104, 1, 1)
        INTO Tab ("Category", "SubCategory", "Date", "GID1", "GID2")
             VALUES ('A', 'bannana', 20120105, NULL, NULL)
        INTO Tab ("Category", "SubCategory", "Date", "GID1", "GID2")
             VALUES ('A', 'pear', 20120106, 2, 2)
        INTO Tab ("Category", "SubCategory", "Date", "GID1", "GID2")
             VALUES ('A', 'pear', 20120107, 2, 2)
        INTO Tab ("Category", "SubCategory", "Date", "GID1", "GID2")
             VALUES ('A', 'apple', 20120108, NULL, NULL)
        INTO Tab ("Category", "SubCategory", "Date", "GID1", "GID2")
             VALUES ('A', 'pear', 20120109, 3, 3)
        INTO Tab ("Category", "SubCategory", "Date", "GID1", "GID2")
             VALUES ('B', 'apple', 20120101, NULL, NULL)
        INTO Tab ("Category", "SubCategory", "Date", "GID1", "GID2")
             VALUES ('B', 'bannana', 20120102, NULL, NULL)
        INTO Tab ("Category", "SubCategory", "Date", "GID1", "GID2")
             VALUES ('B', 'apple', 20120103, NULL, NULL)
        INTO Tab ("Category", "SubCategory", "Date", "GID1", "GID2")
             VALUES ('B', 'bannana', 20120104, NULL, NULL)
        INTO Tab ("Category", "SubCategory", "Date", "GID1", "GID2")
             VALUES ('B', 'pear', 20120105, 1, 4)
        INTO Tab ("Category", "SubCategory", "Date", "GID1", "GID2")
             VALUES ('B', 'pear', 20120106, 1, 4)
        INTO Tab ("Category", "SubCategory", "Date", "GID1", "GID2")
             VALUES ('B', 'pear', 20120107, 1, 4)
        INTO Tab ("Category", "SubCategory", "Date", "GID1", "GID2")
             VALUES ('B', 'pear', 20120108, 1, 4)
        INTO Tab ("Category", "SubCategory", "Date", "GID1", "GID2")
             VALUES ('B', 'pear', 20120109, 1, 4)
        INTO Tab ("Category", "SubCategory", "Date", "GID1", "GID2")
             VALUES ('C', 'grape', 20120101, NULL, NULL)
        INTO Tab ("Category", "SubCategory", "Date", "GID1", "GID2")
             VALUES ('C', 'grape', 20120102, NULL, NULL)
        INTO Tab ("Category", "SubCategory", "Date", "GID1", "GID2")
             VALUES ('C', 'apple', 20120103, NULL, NULL)
        INTO Tab ("Category", "SubCategory", "Date", "GID1", "GID2")
             VALUES ('C', 'bannana', 20120104, NULL, NULL)
        INTO Tab ("Category", "SubCategory", "Date", "GID1", "GID2")
             VALUES ('C', 'grape', 20120105, NULL, NULL)
        INTO Tab ("Category", "SubCategory", "Date", "GID1", "GID2")
             VALUES ('C', 'pear', 20120106, 1, 5)
        INTO Tab ("Category", "SubCategory", "Date", "GID1", "GID2")
             VALUES ('C', 'apple', 20120107, NULL, NULL)
        INTO Tab ("Category", "SubCategory", "Date", "GID1", "GID2")
             VALUES ('C', 'apple', 20120108, NULL, NULL)
        INTO Tab ("Category", "SubCategory", "Date", "GID1", "GID2")
             VALUES ('C', 'apple', 20120109, NULL, NULL)
    SELECT * FROM dual
    ;
4

2 に答える 2

4

洋ナシの場合はOK：

SQL> select "Category", "SubCategory", "Date",
  2         case
  3           when "SubCategory" = 'pear'
  4           then
  5             count(rn) over (partition by "Category" order by "Date") else null
  6         end GID1 ,
  7         case
  8           when "SubCategory" = 'pear'
  9           then
 10             count(rn) over ( order by "Category", "Date") else null
 11         end GID2
 12    from (select "Category", "SubCategory", "Date", lag("SubCategory") over (partition by "Category" order by "Date"),
 13                                    case
 14                                      when lag("SubCategory") over (partition by "Category" order by "Date") != "SubCategory"
 15                                      and "SubCategory" = 'pear'
 16                                       then 1
 17                                      when row_number() over (partition by "Category" order by "Date") = 1 and "SubCategory" = 'pear' then 1
 18                                      else null
 19                                    end rn
 20                               from tab)
 21   order by 1, 3;

Category   SubCate       Date       GID1       GID2
---------- ------- ---------- ---------- ----------
A          bannana   20120101
A          grape     20120102
A          pear      20120103          1          1
A          pear      20120104          1          1
A          bannana   20120105
A          pear      20120106          2          2
A          pear      20120107          2          2
A          apple     20120108
A          pear      20120109          3          3
B          apple     20120101
B          bannana   20120102
B          apple     20120103
B          bannana   20120104
B          pear      20120105          1          4
B          pear      20120106          1          4
B          pear      20120107          1          4
B          pear      20120108          1          4
B          pear      20120109          1          4
C          grape     20120101
C          grape     20120102
C          apple     20120103
C          bannana   20120104
C          grape     20120105
C          pear      20120106          1          5
C          apple     20120107
C          apple     20120108
C          apple     20120109

これを分解します。

「日付」で並べ替えられた前の行を (「カテゴリ」ごとに) 見て、それが別の「サブカテゴリ」であったかどうか、また現在のカテゴリ = pear であることを確認します。その場合は、行に「1」のタグを付けます (使用するものとは関係ありません。NON NULL のみです)。

lag("SubCategory") over (partition by "Category" order by "Date") != "SubCategory" 
 and "SubCategory" = 'pear'

最初の行にも同じものを割り当てます。これにより、次のことがわかります。

Category   SubCate       Date LAG("SU         RN
---------- ------- ---------- ------- ----------
A          bannana   20120101
A          grape     20120102 bannana
A          pear      20120103 grape            1
A          pear      20120104 pear
A          bannana   20120105 pear
A          pear      20120106 bannana          1
A          pear      20120107 pear
A          apple     20120108 pear
A          pear      20120109 apple            1
B          apple     20120101
B          bannana   20120102 apple
B          apple     20120103 bannana
B          bannana   20120104 apple
B          pear      20120105 bannana          1
B          pear      20120106 pear
B          pear      20120107 pear
B          pear      20120108 pear
B          pear      20120109 pear
C          grape     20120101
C          grape     20120102 grape
C          apple     20120103 grape
C          bannana   20120104 apple
C          grape     20120105 bannana
C          pear      20120106 grape            1
C          apple     20120107 pear
C          apple     20120108 apple
C          apple     20120109 apple

ここで、Null でない "RN" 値を Date に再度並べ替えるだけです (GID2[gid2 ではなく、GID1 のカテゴリごとに並べ替えます!)。これは次の行です: count(rn) over (partition by "Category" order by "Date")(GID1)

および count(rn) over ( order by "Category", "Date")(GID2)

于 2012-11-26T23:13:19.853 に答える