4

クエリ1:

SELECT COUNT (A.EMPNO) AS [PRESENT]    
FROM ERPDATA.NIITESS.DBO.ZEMP_MASXST_WEB_AL A INNER                    
JOIN PPA_EVENTWISEEMPLOYEEMASTER B ON 
(CASE B.VC_BA WHEN '%' THEN LTRIM(RTRIM(A.PDIBUSHORT)) ELSE B.VC_BA END) =  LTRIM(RTRIM(A.PDIBUSHORT))                   
AND (CASE B.VC_PA WHEN '%' THEN A.PA ELSE B.VC_PA END) = A.PA                
WHERE A.STATUS = 3  
AND A.EMPNO IN (SELECT VC_EMPCODE FROM ERPDATA.NIITESS.DBO.ADA_MXEASTER WHERE IN_ATTENDANCE_STATUS = 1 AND CH_ACTIVE = 'Y' AND VC_EMPCODE <> '')                    
GROUP BY B.IN_EVENTID

クエリ2:

SELECT COUNT (A.EMPNO) AS [TOTAL]    
FROM ERPDATA.NIITESS.DBO.ZEMP_MASXST_WEB_AL A INNER                    
JOIN PPA_EVENTWISEEMPLOYEEMASTER B ON 
(CASE B.VC_BA WHEN '%' THEN LTRIM(RTRIM(A.PDIBUSHORT)) ELSE B.VC_BA END) =  LTRIM(RTRIM(A.PDIBUSHORT))                   
AND (CASE B.VC_PA WHEN '%' THEN A.PA ELSE B.VC_PA END) = A.PA                
WHERE A.STATUS = 3  

2つの結果を、列がない2つの列にマージしたい=クエリ2-クエリ1-処理速度を速くします。どうすればいいですか?例:
2つの結果があります:
//----------------------------------------クエリ:1
1
2
3
4
// --------------------------------------クエリ:2
4
5
6
8 //------------------------------------ 2

列の結果AS15 2 6 3 7 4 8




4

1 に答える 1

5
Select a.C1-b.C2 as Res
 from
(
Select Count(*) as C1 from Users
Group by Name
) a
join
(
Select Count(*) as C2 from User2
Group by Name
) b ON 1=1 -- or desired condition if existing
于 2012-11-27T07:09:58.833 に答える