3

El Yoboの PHP で Word を数値に変換するという優れた関数があります。しかし、文字列が書かれた数字で始まらなければならないという問題があります。「iPhoneには23万783個のアプリがあります」などを変換するにはどうすればよいですか?

説明された機能：

function wordsToNumber($data) {
// Replace all number words with an equivalent numeric value
$data = strtr(
    $data,
    array(
        'zero'      => '0',
        'a'         => '1',
        'one'       => '1',
        'two'       => '2',
        'three'     => '3',
        'four'      => '4',
        'five'      => '5',
        'six'       => '6',
        'seven'     => '7',
        'eight'     => '8',
        'nine'      => '9',
        'ten'       => '10',
        'eleven'    => '11',
        'twelve'    => '12',
        'thirteen'  => '13',
        'fourteen'  => '14',
        'fifteen'   => '15',
        'sixteen'   => '16',
        'seventeen' => '17',
        'eighteen'  => '18',
        'nineteen'  => '19',
        'twenty'    => '20',
        'thirty'    => '30',
        'forty'     => '40',
        'fourty'    => '40', // common misspelling
        'fifty'     => '50',
        'sixty'     => '60',
        'seventy'   => '70',
        'eighty'    => '80',
        'ninety'    => '90',
        'hundred'   => '100',
        'thousand'  => '1000',
        'million'   => '1000000',
        'billion'   => '1000000000',
        'and'       => '',
    )
);

// Coerce all tokens to numbers
$parts = array_map(
    function ($val) {
        return floatval($val);
    },
    preg_split('/[\s-]+/', $data)
);

$stack = new SplStack; // Current work stack
$sum   = 0; // Running total
$last  = null;

foreach ($parts as $part) {
    if (!$stack->isEmpty()) {
        // We're part way through a phrase
        if ($stack->top() > $part) {
            // Decreasing step, e.g. from hundreds to ones
            if ($last >= 1000) {
                // If we drop from more than 1000 then we've finished the phrase
                $sum += $stack->pop();
                // This is the first element of a new phrase
                $stack->push($part);
            } else {
                // Drop down from less than 1000, just addition
                // e.g. "seventy one" -> "70 1" -> "70 + 1"
                $stack->push($stack->pop() + $part);
            }
        } else {
            // Increasing step, e.g ones to hundreds
            $stack->push($stack->pop() * $part);
        }
    } else {
        // This is the first element of a new phrase
        $stack->push($part);
    }

    // Store the last processed part
    $last = $part;
}

return $sum + $stack->pop();
}
4

5 に答える 5

1

まあ..認めざるを得ない..これは個人的なレベルで私にとって興味深いものでした!!! とにかく...これがコードです...ここでテストできます：http://www.eyerollweb.com/str2digits/

コード自体は次のとおりです。

<?php

//The Test string
$str = "two hundred thousand six hundred and two";

$numbers = array(
    'zero' => 0,
    'one' => 1,
    'two' => 2,
    'three' => 3,
    'four' => 4,
    'five' => 5,
    'six' => 6,
    'seven' => 7,
    'eight' => 8,
    'nine' => 9,
    'ten' => 10,
    'eleven' => 11,
    'twelve' => 12,
    'thirteen' => 13,
    'fourteen' => 14,
    'fifteen' => 15,
    'sixteen' => 16,
    'seventeen' => 17,
    'eighteen' => 18,
    'nineteen' => 19,
    'twenty' => 20,
    'thirty' => 30,
    'forty' => 40,
    'fourty' => 40, // common misspelling
    'fifty' => 50,
    'sixty' => 60,
    'seventy' => 70,
    'eighty' => 80,
    'ninety' => 90,
    'hundred' => 100,
    'thousand' => 1000,
    'million' => 1000000,
    'billion' => 1000000000);

//first we remove all unwanted characters... and keep the text
$str = preg_replace("/[^a-zA-Z]+/", " ", $str);

//now we explode them word by word... and loop through them
$words = explode(" ", $str);

//i devide each thousands in groups then add them at the end
//For example 2,640,234 "two million six hundred and fourty thousand two hundred and thirty four"
//is defined into 2,000,000 + 640,000 + 234

//the $total will be the variable were we will add up to
$total = 1;

//flag to force the next operation to be an addition
$force_addition = false;

//hold the last digit we added/multiplied
$last_digit = null;

//the final_sum will be the array that will hold every portion "2000000,640000,234" which we will sum at the end to get the result
$final_sum = array();

foreach ($words as $word) {

    //if its not an and or a valid digit we skip this turn
    if (!isset($numbers[$word]) && $word != "and") {
        continue;
    }

    //all small letter to ease the comparaison
    $word = strtolower($word);

    //if it's an and .. and this is the first digit in the group we set the total = 0 
    //and force the next operation to be an addition
    if ($word == "and") {
        if ($last_digit === null) {
            $total = 0;
        }
        $force_addition = true;
    } else {
        //if its a digit and the force addition flag is on we sum
        if ($force_addition) {
            $total += $numbers[$word];
            $force_addition = false;
        } else {
            //if the last digit is bigger than the current digit we sum else we multiply
            //example twenty one => 20+1,  twenty hundred 20 * 100
            if ($last_digit !== null && $last_digit > $numbers[$word]) {
                $total += $numbers[$word];
            } else {
                $total *= $numbers[$word];
            }
        }
        $last_digit = $numbers[$word];

        //finally we distinguish a group by the word thousand, million, billion  >= 1000 ! 
        //we add the current total to the $final_sum array clear it and clear all other flags...
        if ($numbers[$word] >= 1000) {
            $final_sum[] = $total;
            $last_digit = null;
            $force_addition = false;
            $total = 1;
        }
    }



}

// there is your final answer !
$final_sum[] = $total;
print "Final Answer: " . array_sum($final_sum) . "\n";

?>
于 2012-11-30T21:27:20.777 に答える
0 
<?php

$string=$_POST['num'];
$array1=array("one"=>1,"two"=>2,"three"=>3,"four"=>4,"five"=>5,"six"=>6,"seven"=>7,"eight"=>8,"nine"=>9,"ten"=>10,"eleven"=>11,"twelve"=>12,"thirteen"=>13,"fourteen"=>14,"fifteen"=>15,"sixteen"=>16,"seventeen"=>17,"eighteen"=>18,"ninteen"=>19,"twenty"=>20,"thirty"=>30,"fourty"=>40,"fifty"=>50,"sixty"=>60,"seventy"=>70,"eighty"=>80,"ninty"=>90);

$array2=array("hundred"=>100,"thousand"=>1000,"lakh"=>100000,"crore"=>10000000);
echo "<br>";
$number=explode(" ",$string);
echo "<br>";
$count=count($number);
$new=0;
$final=0;
foreach($number as $word)
{
    $lastTwo=$lastOne;
    foreach($array1 as $keyCN=>$valueCN)
    {   

        if($keyCN==$word)
        {
            $new=$valueCN;
            $lastOne=$valueCN;
        }
     }

    foreach($array2 as $key=>$value)
    {
         if($key==$word)
         {

            $new2=$new*$value;
            $num+=$new2;
            $lastOne=0;
            $lastTwo=0;
        }
    }   
}
$final=$num+$lastOne+$lastTwo;

echo "final is $final<br>";
?>
<form method="POST">
<input type="text" name="num" value=""></br>
<input type="submit" value="Convert string to number">
</form>
于 2014-06-16T11:29:03.080 に答える
0 
$input = "iPhone has two hundred and thirty thousand, seven hundred and eighty-three apps";
$words = explode(' ', preg_replace("/[^A-Za-z0-9]/", ' ', $input)); //replace non-alpha characters like ',' with ' '
$res_arr = array();

foreach( $input_arr as $word ) {
    if( in_array($word, $number_words) ) { //$number_words being the large array given in your code
        $res_arr[] = $word;
    }
}
$clean_input = implode(' ', $res_arr);
//should look like: two hundred and thirty thousand seven hundred and eighty-three
于 2012-11-30T19:38:20.403 に答える