1

SQL Server クエリについて質問があります。

テーブルは次のように記述できます。

  • サプライヤー( SID, sName, status, sCity)、PK = SID

  • 部分( PID, pName, color, weight, pCity)、PK = PID

  • プロジェクト( JID, jName, city)、PK = JID

  • SPJ ( SID, PID, JID, quantity)、PK = (SID、PID、JID)、FK = SID、PID、JID

同じ部品のサプライヤのサプライヤ番号と名前を少なくとも 2 つのプロジェクトに取得しようとしています。タスクのクエリは次のとおりです。

SELECT 
    s1.SID, s1.sName, COUNT(*)
FROM 
    Suppliers s1, Parts p, SPJ s2
WHERE 
    s1.SID = s2.SID 
    AND p.PID = s2.PID 
GROUP BY 
    s1.SID, s1.sName
HAVING 
    COUNT(*)>1
ORDER BY 
    s1.SID, s1.sName

このクエリを修正するのを手伝ってください。前もって感謝します

4

4 に答える 4

2

これはあなたが求めることを正確に行います：

SELECT
   S.SupplierID,
   S.sName
FROM
   dbo.Suppliers S
WHERE
   EXISTS (
      SELECT *
      FROM dbo.SPJ SPJ
      WHERE S.SupplierID = SPJ.SupplierID
      GROUP BY SPJ.PartID
      HAVING Count(*) >= 2
   );

私の SQLFiddleを参照して、実際のデータ セットで試してみてください。サプライヤーを認定するために参加するすべての個々の行を示すクエリもあることに注意してください (Qualifies列を参照)。セットアップ スクリプトのプレビューを次に示します。

CREATE TABLE dbo.Suppliers (
   SupplierID smallint identity(1,1) NOT NULL CONSTRAINT PK_Suppliers PRIMARY KEY CLUSTERED,
   sName varchar(40) NOT NULL CONSTRAINT UQ_Suppliers_sName UNIQUE
);

CREATE TABLE dbo.Parts (
   PartID int identity(1,1) NOT NULL CONSTRAINT PK_Parts PRIMARY KEY CLUSTERED,
   pName varchar(100) NOT NULL CONSTRAINT UQ_Parts_pName UNIQUE
);

CREATE TABLE dbo.Projects (
   ProjectID int identity(1,1) NOT NULL CONSTRAINT PK_Projects PRIMARY KEY CLUSTERED,
   jName varchar(50) NOT NULL CONSTRAINT UQ_Projects_jName UNIQUE
);

CREATE TABLE dbo.SPJ (
   SupplierID smallint NOT NULL CONSTRAINT FK_SPJ_Suppliers FOREIGN KEY REFERENCES dbo.Suppliers (SupplierID),
   PartID int NOT NULL CONSTRAINT FK_SPJ_Parts FOREIGN KEY REFERENCES dbo.Parts (PartID),
   ProjectID int NOT NULL CONSTRAINT FK_SPJ_Projects FOREIGN KEY REFERENCES dbo.Projects (ProjectID),
   CONSTRAINT PK_SPJ PRIMARY KEY CLUSTERED (SupplierID, PartID, ProjectID)
);

INSERT dbo.Suppliers
VALUES
   ('Joe'' Specialty Goods'),
   ('Major Supplier'),
   ('Small Supplier'),
   ('Tamandua Manufacturing, Ltd.'),
   ('Things ''n'' Stuff'),
   ('Stuff ''n'' Things');

INSERT dbo.Parts
VALUES
   ('Watchamacallit'),
   ('Thingamajiggy'),
   ('Thingamabob'),
   ('Doohickey'),
   ('Whatsisname'),
   ('Thingy'),
   ('Gizmo'),
   ('Gadget'),
   ('Widget'),
   ('Titanium Widget'),
   ('Electronic Thingamabob'),
   ('One-Product Patrick');

INSERT dbo.Projects
VALUES
   ('Video Game Manufacturing'),
   ('Autodoc Research'),
   ('Consumer Electronics Expansion'),
   ('Space Shuttle'),
   ('Tablet Project Cobalt');

INSERT dbo.SPJ
VALUES
   (1, 2, 1),
   (1, 3, 1),
   (1, 7, 1),
   (1, 11, 1),
   (2, 1, 1),
   (2, 1, 2),
   (2, 1, 3),
   (2, 1, 4),
   (2, 2, 1),
   (2, 2, 2),
   (2, 2, 3),
   (2, 2, 4),
   (2, 2, 5),
   (2, 10, 1),
   (2, 10, 2),
   (2, 10, 3),
   (2, 10, 4),
   (2, 10, 5),
   (3, 5, 4),
   (4, 4, 2),
   (4, 4, 3),
   (5, 9, 1),
   (5, 8, 2),
   (5, 7, 3),
   (5, 6, 4),
   (5, 5, 5),
   (6, 1, 1),
   (6, 2, 1),
   (6, 3, 1),
   (6, 4, 1),
   (6, 5, 1),
   (6, 6, 1),
   (6, 7, 1),
   (6, 8, 1),
   (6, 9, 1),
   (6, 10, 1),
   (6, 11, 1);
于 2012-12-08T19:25:47.240 に答える
0

次のようにすることもできます。

SELECT DISTINCT
a.SupplierID,
b.sName
FROM
(
  SELECT
   SupplierID,
   PartID,
   NumProjects = count(DISTINCT ProjectID)
  FROM SPJ
  GROUP BY
   SupplierID, PartID
  HAVING 
   count(DISTINCT ProjectID) >= 2 
) a
INNER JOIN Suppliers b ON a.SupplierID = b.SupplierID
于 2012-12-09T22:27:43.713 に答える
0 
SELECT SID, PID, COUNT(JID)
FROM SPJ
GROUP BY SID, PID
HAVING COUNT(JID) > 1
于 2012-12-08T03:21:15.783 に答える
-1 
SELECT Supplier.SID,Supplier.sName
FROM SPJ inner join Supplier on SPJ.SID = Supplier.SID
inner join Parts on SPJ.PID = Parts.PID
GROUP BY Supplier.SID,Supplier.sName
HAVING COUNT(JID) > 1
于 2012-12-08T05:12:07.243 に答える