上記の問題に対する答えではなく、同様の行にあります。
配列の要素を順番に印刷するようにプログラムしますが、2つの異なるスレッドを使用して隣接する要素を印刷します
import java.util.logging.Level;
import java.util.logging.Logger;
/**
*
* @author ntv
*/
public class PrintLAternateNumber {
public static void main(String[] args) {
int [] num = {1,2,3,4,5,6};
Printer p = new Printer();
Thread t1 = new Thread(new Thread1(num, p), "Thread1");
Thread t2 = new Thread(new Thread2(num, p), "Thread2");
t1.start();
t2.start();
}
}
class Thread1 implements Runnable {
int [] num;
Printer p ;
public Thread1(int[] num, Printer p) {
this.num = num;
this.p = p;
}
public void run() {
try {
print();
} catch (InterruptedException ex) {
Logger.getLogger(Thread1.class.getName()).log(Level.SEVERE, null, ex);
}
}
public void print() throws InterruptedException {
int i = 1;
while(i < num.length) {
synchronized(num) {
while (p.evenPrinted) {
num.wait();
}
}
synchronized(num) {
p.printEven(Thread.currentThread().getName(), num[i]);
i= i + 2;
num.notifyAll();
}
}
}
}
class Thread2 implements Runnable {
int [] num;
Printer p ;
public Thread2(int[] num, Printer p) {
this.num = num;
this.p = p;
}
public void run() {
try {
print();
} catch (InterruptedException ex) {
Logger.getLogger(Thread2.class.getName()).log(Level.SEVERE, null, ex);
}
}
public void print() throws InterruptedException {
int i = 0;
while(i < num.length) {
synchronized(num) {
while (!p.evenPrinted) {
num.wait();
}
}
synchronized(num) {
p.printOdd(Thread.currentThread().getName(), num[i]);
i = i + 2;
num.notifyAll();
}
}
}
}
class Printer {
boolean evenPrinted = true;
void printEven(String threadName , int i) {
System.out.println(threadName + "," + i);
evenPrinted = true;
}
void printOdd(String threadName , int i) {
System.out.println(threadName + "," + i);
evenPrinted = false;
}
}