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$sql_pay_det クエリを $sql_pay ループの外に移動する方法を見つけようとしています (したがって、ループの反復ごとに新しい $rs_pay_det を作成するのではなく、実際には $rs_pay_det に対してクエリを実行します)。

現時点では、私のコードは次のようになります。

        //Get payroll transactions
        $sql_pay = 'SELECT Field1, DescriptionandURLlink, Field5, Amount, Field4, PeriodName FROM tblgltransactionspayroll WHERE CostCentreCode = "'.$cc.'" AND SubjectiveCode = "'.$subj.'" AND PeriodNo = "'.$month.'"';
        $rs_pay = mysql_query($sql_pay);
        $row_pay = mysql_fetch_assoc($rs_pay);

            while($row_pay = mysql_fetch_array($rs_pay))
              {
                    $employee_name = $row_pay['Field1'];
                    $assign_no = $row_pay['DescriptionandURLlink'];
                    $pay_period = $row_pay['Field5'];
                    $mth_name = $row_pay['PeriodName'];
                    $amount = $row_pay['Amount'];
                    $total_amount = $total_amount + $amount;
                    $amount = my_number_format($amount, 2, ".", ",");

                    $sql_pay_det = 'SELECT ElementDesc, Amount, WTEWorked, WTEPaid, WTEContract, Payscale FROM tblpayrolldetail WHERE CostCentreCode = "'.$cc.'" AND SubjectiveCode = "'.$subj.'" AND AccountingPeriod = "'.$mth_name.'" AND EmployeeRef = "'.$assign_no.'"';
                    $rs_pay_det = mysql_query($sql_pay_det);
                    $row_pay_det = mysql_fetch_assoc($rs_pay_det);

                while($row_pay_det = mysql_fetch_array($rs_pay_det))
                {
                    $element_det = $row_pay_det['ElementDesc'];
                    $amount_det = $row_pay_det['Amount'];
                    $wte_worked = $row_pay_det['WTEWorked'];
                    $wte_paid = $row_pay_det['WTEPaid'];
                    $wte_cont = $row_pay_det['WTEContract'];
                    $payscale = $row_pay_det['Payscale'];

                    //Get band/point and annual salary where element is basic pay
                    if ($element_det =="3959#Basic Pay"){
                        $sql_payscale = 'SELECT txtPayscaleName, Salary FROM tblpayscalemapping WHERE txtPayscale = "'.$payscale.'"';
                        $rs_payscale = mysql_query($sql_payscale);
                        $row_payscale = mysql_fetch_assoc($rs_payscale);

                        $grade = $row_payscale['txtPayscaleName'];
                        $salary = "£" . my_number_format($row_payscale['Salary'], 0, ".", ",");

                    }
                }
            }

私はこれをやってみました：

        //Get payroll transactions
        $sql_pay = 'SELECT Field1, DescriptionandURLlink, Field5, Amount, Field4, PeriodName FROM tblgltransactionspayroll WHERE CostCentreCode = "'.$cc.'" AND SubjectiveCode = "'.$subj.'" AND PeriodNo = "'.$month.'"';
        $rs_pay = mysql_query($sql_pay);
        $row_pay = mysql_fetch_assoc($rs_pay);

        //Get payroll detail recordset
        $sql_pay_det = 'SELECT ElementDesc, Amount, WTEWorked, WTEPaid, WTEContract, Payscale, EmployeeRef FROM tblpayrolldetail WHERE CostCentreCode = "'.$cc.'" AND SubjectiveCode = "'.$subj.'" AND AccountingPeriod = "'.$mth_name.'"';
        $rs_pay_det = mysql_query($sql_pay_det);

            while($row_pay = mysql_fetch_array($rs_pay))
              {
                    $employee_name = $row_pay['Field1'];
                    $assign_no = $row_pay['DescriptionandURLlink'];
                    $pay_period = $row_pay['Field5'];
                    $mth_name = $row_pay['PeriodName'];
                    $amount = $row_pay['Amount'];
                    $total_amount = $total_amount + $amount;
                    $amount = my_number_format($amount, 2, ".", ",");

                    //Query $rs_pay_det
                    $sql_pay_det2 = 'SELECT ElementDesc, Amount, WTEWorked, WTEPaid, WTEContract, Payscale FROM ('.$sql_pay_det.') tpd WHERE EmployeeRef = "'.$assign_no.'"';
                    $rs_pay_det2 = mysql_query($sql_pay_det2);
                    $row_pay_det2 = mysql_fetch_assoc($rs_pay_det2);

                while($row_pay_det2 = mysql_fetch_array($rs_pay_det2))
                {
                    $element_det = $row_pay_det2['ElementDesc'];
                    $amount_det = $row_pay_det2['Amount'];
                    $wte_worked = $row_pay_det2['WTEWorked'];
                    $wte_paid = $row_pay_det2['WTEPaid'];
                    $wte_cont = $row_pay_det2['WTEContract'];
                    $payscale = $row_pay_det2['Payscale'];

                    //Get band/point and annual salary where element is basic pay
                    if ($element_det =="3959#Basic Pay"){
                        $sql_payscale = 'SELECT txtPayscaleName, Salary FROM tblpayscalemapping WHERE txtPayscale = "'.$payscale.'"';
                        $rs_payscale = mysql_query($sql_payscale);
                        $row_payscale = mysql_fetch_assoc($rs_payscale);

                        $grade = $row_payscale['txtPayscaleName'];
                        $salary = "£" . my_number_format($row_payscale['Salary'], 0, ".", ",");

                    }
                }
            }

しかし、$row_pay_det2 で「mysql_fetch_assoc(): 提供された引数は有効な MySQL 結果リソースではありません」というエラーが表示されます。

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1 に答える 1

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構文subquery( ... FROM "'.$rs_pay_det.'" ...) が間違っています。

マニュアルによると - dev.mysql.com/doc/refman/5.0/en/from-clause-subqueries.html

サブクエリは、SELECT ステートメントの FROM 句で有効です。実際の構文は次のとおりです。

SELECT ... FROM (サブクエリ) [AS] 名前 ...

に変更してみてください-

$sql_pay_det2 = 'SELECT ElementDesc, Amount, WTEWorked, WTEPaid, WTEContract, Payscale FROM ('.$sql_pay_det.') tpd WHERE EmployeeRef = "'.$assign_no.'"';

編集 - 問題＃2

moves the internal data pointer aheadusing mysql_fetch_assoc(). _ そのmysql_fetch_array()ため、最初の行を除くすべての行が取得されます。

    //Get payroll transactions
    ...
    $row_pay = mysql_fetch_assoc($rs_pay);

    //Get payroll detail recordset
    ...

        while($row_pay = mysql_fetch_array($rs_pay))
          {
                ...
                $row_pay_det2 = mysql_fetch_assoc($rs_pay_det2);

            while($row_pay_det2 = mysql_fetch_array($rs_pay_det2))
            {
                ...
                }
            }
        }

$row_pay = mysql_fetch_assoc($rs_pay);- &を削除する必要があります$row_pay_det2 = mysql_fetch_assoc($rs_pay_det2);

于 2012-12-09T18:56:51.327 に答える