2

ユーザー認証システムのjsonを解析しています。

ログインが成功すると、サーバーは次のユーザー オブジェクトを送信します。

{

    "users": {
        "id": "1",
        "FB_first_name": null,
        "FB_last_name": null,
        "FB_gender": null,
        "FB_id": null,
        "FB_link": null,
        "FB_locale": null,
        "FB_name": null,
        "FB_username": null,
        "created_at": "2011-01-02 08:30:59 UTC",
        "updated_at": "2011-01-02 08:31:23 UTC",
        "email": "admin@8repz.com",
        "language_id": "1"
    }

}

次のコードを使用して解析します。

    NSDictionary *userDic = (NSDictionary*)[(NSDictionary*)results objectForKey:@"users"];

    User *aUser = [[User alloc] initWithID:[userDic objectForKey:@"id"]
                              withUserName:[userDic objectForKey:@"FB_name"]
                             withUserEmail:[userDic objectForKey:@"email"]
                             withUserFName:[userDic objectForKey:@"FB_first_name"]];

ただし、無効なユーザーの場合、サーバーは次の応答を送信します。

[

    "Invalid Email or Password."

]

両方の条件で応答を解析して表示するには、どのif()ステートメントを使用すればよいですか?

4

2 に答える 2

4 
//parse out the json data
NSError* error;
id json = [NSJSONSerialization JSONObjectWithData:responseData options:NSJSONReadingMutableContainers error:&error];
if ([json isKindOfClass:[NSArray class]){
    //You have to be sure that on error it returns array not a dictionary
    NSArray *arr = (NSArray*)json;
    NSString *errorMsg = [arr objectAtIndex:0];
}
else {

}
于 2012-12-11T14:29:30.583 に答える
0 
//IF RESPONSE IS SIMPLY A STRING OBJECT FOR INVALID STRING, YOU HAVE BAD DATA
if(![results isEqualToString:@"Invalid Email or Password."]){
     if([results objectForKey:@"users"]){  //Check to ensure users object exists
          //You're good 
           NSDictionary *userDic = (NSDictionary*)[(NSDictionary*)results objectForKey:@"users"];

            User *aUser = [[User alloc] initWithID:[userDic objectForKey:@"id"]
                              withUserName:[userDic objectForKey:@"FB_name"]
                             withUserEmail:[userDic objectForKey:@"email"]
                             withUserFName:[userDic objectForKey:@"FB_first_name"]];
     }
}else{
     //Handle error
}
于 2012-12-11T13:39:39.593 に答える