javascript - TypeScript と ExactEqual

Question

2 つのオブジェクトが等しいかどうかを最も簡単な方法で確認する方法は? メソッドのようなものがないことに気づいたExactEqual()ので、手動で行うべきかどうかを考えています。

助けてくれてありがとう！

Answer 1

そのような方法はありません。このjqfaq.comリンクを見てください。ここで議論され、確認する最良の方法が示されています。これは、 typescriptと javascriptの両方に適しています。うまくいけば、それはあなたを助けるでしょう!.

その答えの最も重要な部分を引用するには：

//“===” means that they are identical.
//“==” means that they are equal in value.
//( == )
//Each JavaScript value is of a specific “type” (Numbers, strings, Booleans, functions, and objects). So if you try to compare a string with a number, the browser will try to convert the string into a number before doing the comparison.
//So the following will return true.
55 == “55″ //true
0 == false //true
1 == true //true
//(===)
//The === operator will not do the conversion, if two values are not the same type it will return false. In other words, this returns true only if the operands are strictly equal in value or if they are identical objects.
55 === “55″ //false
0 === false //false
1 === true //false
var a = [1, 2, 3];
var b = [1, 2, 3];
var c = a;
var is_ab_eql = (a === b); // false (Here a and b are the same type,and also have the same value)
var is_ac_eql = (a === c); // true.
//Value types (numbers):
//a === b returns true if a and b have the same value and are of the same type.
//Reference types:
//a === b returns true if a and b reference the exact same object.
//Strings:
//a === b returns true if a and b are both strings and contain the exact same characters.
var a = “ab” + “c”;
var b = “abc”;
a === b //true
a == b //true
//in thiss case the above condition will fail
var a = new String(“abc”);
var b = “abc”;
a === b //false
a == b// true
//… since a and b are not a same type.
typeof “abc”; // ‘string’
typeof new String(“abc”)); // ‘object