私はこれを見て何時間も費やしましたが、間違いはわかりません。
6列、6?、6配列要素。うまくいくの
が問題です!
ところで。これは対処するのに良い方法ですか?insert
update
insert on duplicate update
$userId = 13;
foreach($tableKey as $table=>$value){
foreach($value as $key=>$val){
$array_of_parameters[$key] = $val;
$fields[] = sprintf("%s=?", $key);
}
$field_list = join(', ', $fields);
try{
$update = "UPDATE `$table` SET $field_list WHERE id=$userId";
$stmt = $db->prepare($update);
echo $stmt->debugDumpParams();
$stmt->execute($array_of_parameters);// here's where I get error!
if($stmt->rowCount() == 0){
$insert = "INSERT INTO `$table` (".implode(',', array_keys($value)).") VALUES (:".implode(',:', array_keys($value)).")";
$stmt = $db->prepare($insert);
echo $stmt->debugDumpParams();
$stmt->execute($array_of_parameters);
}
}
}
これdebug
が$array_of_parameters
array
'user' => string 'somebody' (length=3)
'first' => string 'some' (length=7)
'last' => string 'body' (length=4)
'zoneId' => string 'zone' (length=4)
'email' => string 'tst@me.net' (length=21)
'head' => string '1' (length=1)
SQL: [80] UPDATE `user` SET user=?, first=?, last=?, zoneId=?, email=?, head=? WHERE id=13 Params: 0
そしてもちろんerror
Warning: PDOStatement::execute() [pdostatement.execute]: SQLSTATE[HY093]: Invalid parameter number: parameter was not defined