1

GoogleMapServerからの応答を表示したい。取得した応答は、緯度と経度をGoogleマップサーバーに送信した後に取得した場所の名前であり、応答は「av delaRépublique」のようになりますが、これをアプリに表示すると、応答を解析すると、「av delaRÃ（c）publique」と表示されます。

以下のコードスニペットは、私の問題を理解するのに役立つかもしれません。

public static String getAddress(double lat, double lon){
        StringBuilder stringBuilder = new StringBuilder();
         String add ="";

       try {

        HttpPost httppost = new HttpPost("http://maps.googleapis.com/maps/api/geocode/json?latlng="+lat+","+lon+"&sensor=false");
        HttpClient client = new DefaultHttpClient();
        org.apache.http.HttpResponse response;
        stringBuilder = new StringBuilder();

            response = client.execute(httppost);
            HttpEntity entity = response.getEntity();
            InputStream stream = entity.getContent();
            int b;
            while ((b = stream.read()) != -1) {
                stringBuilder.append((char) b);
            }
        } catch (ClientProtocolException e) {
        } catch (IOException e) {
        }

        JSONObject jsonObject = new JSONObject();
        try {
            jsonObject = new JSONObject(stringBuilder.toString());
        } catch (JSONException e) {
            // TODO Auto-generated catch block
            e.printStackTrace();
        }

       try {
          add = ((JSONArray)jsonObject.get("results")).getJSONObject(0)
               .getString("formatted_address");
       } catch (Exception e) {
           e.printStackTrace();
       }
       return add;
    }

これは私のコードの実装です

public static String getAddress(double lat, double lon){
        StringBuilder stringBuilder = new StringBuilder();
         String add ="";
        try {

        HttpPost httppost = new HttpPost("http://maps.googleapis.com/maps/api/geocode/json?latlng="+lat+","+lon+"&sensor=false");
        HttpClient client = new DefaultHttpClient();
        org.apache.http.HttpResponse response;
        stringBuilder = new StringBuilder();


            response = client.execute(httppost);
            HttpEntity entity = response.getEntity();

            char[] buffer = new char[2048];
            Reader reader = new InputStreamReader(entity.getContent(), "UTF-8");
            while (true) {
                int n = reader.read(buffer);
                if (n < 0) {
                    break;
                }
                stringBuilder.append(buffer, 0, n);
            }
        } catch (ClientProtocolException e) {
        } catch (IOException e) {
        }

        JSONObject jsonObject = new JSONObject();
        try {
            Log.i("===================", stringBuilder.toString());
            jsonObject = new JSONObject(stringBuilder.toString());
        } catch (JSONException e) {
            // TODO Auto-generated catch block
            e.printStackTrace();
        }


       try {

          add = ((JSONArray)jsonObject.get("results")).getJSONObject(0)
               .getString("formatted_address");

       } catch (Exception e) {
           e.printStackTrace();

       }

       return add;

    }
4

2 に答える 2

2

テキストではなくバイトとしてテキストを読み取っています。実際にはUTF-8である場合、これはISO-8859-1で応答を読み取ることになります。

これを試して：

char[] buffer = new char[2048];
Reader reader = new InputStreamReader(entity.getContent(), "UTF-8");
StringBuilder stringBuilder = new StringBuilder();

while (true) {
    int n = reader.read(buffer);
    if (n < 0) {
        break;
    }
    stringBuilder.append(buffer, 0, n);
}

ここでは、コードに統合されています。

public static String getAddress(double lat, double lon){
    StringBuilder stringBuilder = new StringBuilder();
    String add ="";

    try {

        HttpPost httppost = new HttpPost("http://maps.googleapis.com/maps/api/geocode/json?latlng="+lat+","+lon+"&sensor=false");
        HttpClient client = new DefaultHttpClient();
        org.apache.http.HttpResponse response;
        stringBuilder = new StringBuilder();
        response = client.execute(httppost);
        HttpEntity entity = response.getEntity();

        char[] buffer = new char[2048];
        Reader reader = new InputStreamReader(entity.getContent(), "UTF-8");
        while (true) {
            int n = reader.read(buffer);
            if (n < 0) {
                break;
            }
            stringBuilder.append(buffer, 0, n);
        }

    } catch (ClientProtocolException e) {

    } catch (IOException e) {

    }

    JSONObject jsonObject = new JSONObject();
    try {
        jsonObject = new JSONObject(stringBuilder.toString());
    } catch (JSONException e) {
        // TODO Auto-generated catch block
        e.printStackTrace();
    }

    try {
        add = ((JSONArray)jsonObject.get("results")).getJSONObject(0)
        .getString("formatted_address");
    } catch (Exception e) {
        e.printStackTrace();
    }
    return add;
}
于 2012-12-18T16:55:26.120 に答える