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データ (JArray):

[{ provinceid: "1", provincename: "北京", cityid: "33", cityname: "北京", jp: "bj", quanpin: "beijing" },
{ provinceid: "1", provincename: "北京", cityid: "600", cityname: "朝阳(北京)", jp: "cy", quanpin: "chaoyang" },
{ provinceid: "1", provincename: "北京", cityid: "601", cityname: "通州(北京)", jp: "tz", quanpin: "tongzhou" },
{ provinceid: "1", provincename: "北京", cityid: "46", cityname: "昌平", jp: "cp", quanpin: "changping" },
{ provinceid: "1", provincename: "北京", cityid: "602", cityname: "顺义", jp: "sy", quanpin: "shunyi" }]

調子：

cityname == "北京"

望ましい結果 (JObject):

{ provinceid: "1", provincename: "北京", cityid: "33", cityname: "北京", jp: "bj", quanpin: "beijing" }

質問: 条件を使用して、弱く型付けされたコードでデータから結果を取得する方法は?

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1 に答える 1

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using Newtonsoft.Json;
using System.Collections.Generic;
using System.Linq;

...

public class City
{
    public int provinceid { get; set; }
    public string provincename { get; set; }
    public int cityid { get; set; }
    public string cityname { get; set; }
}

public void FindCity()
{
    string json = @"[{ provinceid: ""1"", provincename: ""北京"", cityid: ""33"", cityname: ""北京"", jp: ""bj"", quanpin: ""beijing"" }, { provinceid: ""1"", provincename: ""北京"", cityid: ""600"", cityname: ""朝阳(北京)"", jp: ""cy"", quanpin: ""chaoyang"" }, { provinceid: ""1"", provincename: ""北京"", cityid: ""601"", cityname: ""通州(北京)"", jp: ""tz"", quanpin: ""tongzhou"" }, { provinceid: ""1"", provincename: ""北京"", cityid: ""46"", cityname: ""昌平"", jp: ""cp"", quanpin: ""changping"" }, { provinceid: ""1"", provincename: ""北京"", cityid: ""602"", cityname: ""顺义"", jp: ""sy"", quanpin: ""shunyi"" }]";

    List<City> cities = JsonConvert.DeserializeObject<List<City>>(json);
    City 北京 = cities.Where(city => city.cityname == "北京").First();
}
于 2013-01-13T08:41:23.997 に答える