python-2.7 - sqlalchemyでこのSQLを生成する方法、私は一生懸命努力していますが、何をすべきかわかりませんでした

Question

"select pck.id、pck.name、deb.last_time from（select id、name from dp_package where name like％s limit％s、％s）as pck left join（select package_id、last_time from dp_deb where id in（select max （id）from dp_deb group by package_id））as deb on pck.id = deb.package_id "％（keyword、start、limit）

Answer 1

モデルが定義されていると仮定します。Base=declarative_base（）

class Package(Base):
    __tablename__ = 'db_package'
    id = Column(Integer, primary_key=True)
    name = Column(String)
    def __init__(self, name):
        self.name = name

class Deb(Base):
    __tablename__ = 'db_deb'
    id = Column(Integer, primary_key=True)
    package_id = Column(Integer, ForeignKey('db_package.id'))
    name = Column(String)
    last_time = Column(DateTime)
    def __init__(self, name, last_time):
        self.name = name
        self.last_time = last_time

    packages = relationship(Package, backref="debs")

以下のコードは同じ結果を生成するはずです（ただし、SQLクエリは異なりsubquery、単純なものに置き換えられますLEFT OUTER JOIN）。

# query parameters
keyword, start, limit = 'xxx', 1, 3

# subquery for the last_time
sq2h = session.query(Deb.package_id, func.max(Deb.id).label("max_id")).group_by(Deb.id).subquery("max_deb")
sq2 = (session.query(Deb.package_id, Deb.last_time).
        join(sq2h, Deb.id == sq2h.c.max_id))
sq2 = sq2.subquery("deb")

qry = (session.query(Package.id, Package.name, sq2.c.last_time).
        outerjoin(sq2, sq2.c.package_id == Package.id).
        filter(Package.name.contains(keyword))
        )[start:(start + limit)]
print qry

SQLのためにこれを生成するSQLite：

SELECT  db_package.id AS db_package_id, 
        db_package.name AS db_package_name, 
        deb.last_time AS deb_last_time
FROM    db_package 
LEFT OUTER JOIN(SELECT  db_deb.package_id AS package_id, db_deb.last_time AS last_time
                FROM    db_deb 
                JOIN   (SELECT  db_deb.package_id AS package_id, 
                                max(db_deb.id) AS max_id
                        FROM    db_deb 
                        GROUP BY db_deb.id
                       ) AS max_deb 
                  ON db_deb.id = max_deb.max_id
        ) AS deb 
    ON  deb.package_id = db_package.id
WHERE   db_package.name LIKE '%%' || ? || '%%'
LIMIT ? OFFSET ?

('xxx', 3, 1)