mysql - mysqlでselectで内部結合を使用するには?

Question

次の条件でmysqlデータベースからレコードをフェッチしたい

次のテーブルがあります。

組織_表
```
organizationId | organizationname
```

キャンペーン表

camp_id | camp_name | adv_id | organizationId

アドバタイズテーブル
```
adv_id | adv_name
```
ad_display テーブル
```
ad_displayId | adv_id | camp_id |
```

今 ad_display テーブルから、次のようなレコードを取得したい:

| adv_name | camp_name | organizationname

条件として Where organizationId WHERE== ?

基本的に、organization_id=? キャンペーンの広告リストが必要です。

注: キャンペーンテーブルに同じ adv_id の複数のエントリがあり、ad_display に複数のエントリがある同じ camp_id が必要です。

score 7 · Accepted Answer

これを試して：

SELECT ad.ad_displayId, a.adv_name, c.camp_name, o.organizationname 
FROM ad_display ad 
INNER JOIN advertise a ON ad.adv_id = a.adv_id 
INNER JOIN campaign c ON ad.camp_id = c.camp_id 
INNER JOIN organization o ON c.organizationId = o.organizationId 
WHERE o.organizationId = ?;

score 2 · Accepted Answer

多分このようなもの？

SELECT Distinct
  advertise.adv_name,
  campaign.camp_name,
  organization_.organizationname
FROM
  advertise inner join campaign
  on advertise.adv_id = campaign.adv_id
  inner join organization_
  on campaign.organizationID = organization_.organizationID
WHERE
  organization_.organizationID = 1

score 1 · Accepted Answer

SELECT * FROM campaign
LEFT JOIN ad_display ON campaign.camp_id = ad_display.camp_id
LEFT JOIN advertise ON ad_display.adv_id = advertise.adv_id
WHERE campaign.organizationId = <?>

score 1 · Accepted Answer

SELECT  advertise.adv_name, 
        campaign.camp_name, 
        organization_Table.organizationname
FROM   ad_display 
    INNER JOIN advertise ON ad_display.adv_id = advertise.adv_id 
    INNER JOIN campaign ON ad_display.camp_id = campaign.camp_id 
    INNER JOIN organization_ Table ON campaign.organizationId = organization_Table.organizationId
    AND organization_Table.organizationId=?

score 1 · Accepted Answer

以下のコードを使用

SELECT dv_name,
       camp_name,
       organizationname
FROM   organization
       inner join campaign
               ON organization.organizationid == campaign.organizationid
       left join advertise
              ON campaign.adv_id == advertise.adv_id
WHERE  condition =? ;

score -1 · Accepted Answer

SELECT batch_number,
       Count(receipt_number) AS tot_rec,
       Sum(amount)           AS tot_amount
FROM   receipt_header
GROUP  BY batch_number
UNION ALL
SELECT batch_number,
       Count(receipt_lines.receipt_number),
       Sum(receipt_lines.amount)
FROM   receipt_lines
       INNER JOIN receipt_header
               ON receipt_header.record_id = receipt_lines.header_record_id
GROUP  BY batch_number
ORDER  BY batch_number ASC;

mysql - mysqlでselectで内部結合を使用するには?

6 に答える 6

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