0

次のようなテーブルがあります。

+---------+---------+-----------------------------------------+
| type    | city    | name                                    |
+---------+---------+-----------------------------------------+
| cricket | kolkata | Khadim's Ashok Malhotra Cricket Academy |
| cricket | kolkata | Calcutta Cricket Coaching Center (C4)   |
| cricket | kolkata | Sambaran Banerjee Cricket academy       |
| cricket | kolkata | Bournvita cricket acadamemy of arun lal |
| cricket | kolkata | friends of the stadium                  |
| cricket | kolkata | pankaj roy cricket academy              |
| cricket | kolkata | sunil gavaskar cricket foundation       |
| cricket | kolkata | castlewood india                        |
| cricket | kolkata | GK sports                               |
| cricket | kolkata | NULL                                    |
| cricket | kolkata | NULL                                    |
| cricket | kolkata | NULL                                    |
| cricket | kolkata | NULL                                    |
| cricket | kolkata | NULL                                    |
| cricket | kolkata | NULL                                    |
+---------+---------+-----------------------------------------+

の代わりに別の名前を付けたいのですがNULL、どうすればよいですか?

4

2 に答える 2

0

これも使用できます:

で始まりますname

select * from table_name where name like "Cricket%"

どこにでも含まれています

select * from table_name where name like "%Cricket%"

で終わる

select * from table_name where name like "%Cricket"
于 2012-12-29T20:49:02.170 に答える
0

試すIFNULL

Select IFNULL(name,'Jon Smith') as name from myTable

name の値が null のときに研究所の名前が必要な場合は、次のことができます::

Select IFNULL(name,institute) as name from myTable
于 2012-12-29T20:19:22.617 に答える