2

私は以下を含むテーブルを持っています：

ID    low_value     high_value
1     3270200000    3270210000
2     3270210000    3270220000
3     3270220000    3270230000
4     3270230000    3270231000
5     3270231000    3270232000
6     3270232000    3270240000
...

Oracle 11gを使用した1つのクエリで、次の結果を取得したいと思います。この結果では、で定義された範囲内に存在する一意の番号をそれぞれリストしています。

start value = with low_value /
end value = high_value - 1

 

low_value   high_value    unique_value
3270200000  3270210000    3270200000    
3270200000  3270210000    3270200001
3270200000  3270210000    3270200002
3270200000  3270210000    3270200003
...
3270200000  3270210000    3270209999
3270210000  3270220000    3270210001
3270210000  3270220000    3270210002
3270210000  3270220000    3270210002
...
3270210000  3270220000    3270219999
...

私はconnectby＆model句で遊んでいますが、これまでのところ成功していません。

あなたの助けのためのtx

4

1 に答える 1

5

モデル句の使用：

SQL> create table foo1
  2  (id number,
  3  low_value number,
  4  high_value number);

Table created.

SQL>
SQL> insert into foo1 values (1,  3270200000, 3270200010);

1 row created.

SQL> insert into foo1 values (2,  3270210000, 3270210005);

1 row created.

SQL> insert into foo1 values (3,  10, 10);

1 row created.

SQL> commit;

Commit complete.

SQL>
SQL>
SQL> with foo as
  2   (select f.id, f.low_value, f.high_value, f.high_value - f.low_value
  3     range from foo1 f)
  4  select key, low_value, high_value, unique_value
  5    from foo
  6   model partition by(id as key)
  7         dimension by(0 as f)
  8         measures(low_value as unique_value, low_value, high_value, range)
  9         rules (unique_value [for f from 0 to range[0]  increment 1]  = low_value[0] + cv(f),
 10               low_value[for f from 0 to range[0]  increment 1] = low_value[0],
 11               high_value[for f from 0 to range[0]  increment 1] = high_value[0]);

       KEY  LOW_VALUE HIGH_VALUE UNIQUE_VALUE
---------- ---------- ---------- ------------
         1 3270200000 3270200010   3270200000
         1 3270200000 3270200010   3270200001
         1 3270200000 3270200010   3270200002
         1 3270200000 3270200010   3270200003
         1 3270200000 3270200010   3270200004
         1 3270200000 3270200010   3270200005
         1 3270200000 3270200010   3270200006
         1 3270200000 3270200010   3270200007
         1 3270200000 3270200010   3270200008
         1 3270200000 3270200010   3270200009
         1 3270200000 3270200010   3270200010
         2 3270210000 3270210005   3270210000
         2 3270210000 3270210005   3270210001
         2 3270210000 3270210005   3270210002
         2 3270210000 3270210005   3270210003
         2 3270210000 3270210005   3270210004
         2 3270210000 3270210005   3270210005
         3         10         10           10

18 rows selected.

SQL>

および11gの再帰的因数分解

SQL> with foo (id, low_value, high_value, unique_value)
  2        as (select f.id, f.low_value, f.high_value, low_value unique_value
  3              from foo1 f
  4             union all
  5            select id, low_Value, high_value, unique_value + 1
  6              from foo
  7             where unique_value < high_value)
  8  select id, low_value, high_value, unique_value
  9    from foo
 10   order by id, unique_value
 11  /

        ID  LOW_VALUE HIGH_VALUE UNIQUE_VALUE
---------- ---------- ---------- ------------
         1 3270200000 3270200010   3270200000
         1 3270200000 3270200010   3270200001
         1 3270200000 3270200010   3270200002
         1 3270200000 3270200010   3270200003
         1 3270200000 3270200010   3270200004
         1 3270200000 3270200010   3270200005
         1 3270200000 3270200010   3270200006
         1 3270200000 3270200010   3270200007
         1 3270200000 3270200010   3270200008
         1 3270200000 3270200010   3270200009
         1 3270200000 3270200010   3270200010

        ID  LOW_VALUE HIGH_VALUE UNIQUE_VALUE
---------- ---------- ---------- ------------
         2 3270210000 3270210005   3270210000
         2 3270210000 3270210005   3270210001
         2 3270210000 3270210005   3270210002
         2 3270210000 3270210005   3270210003
         2 3270210000 3270210005   3270210004
         2 3270210000 3270210005   3270210005
         3         10         10           10

18 rows selected.

SQL>
于 2013-01-02T11:58:25.360 に答える