XML タグ内の MessageParam を XXYY1 に置き換えようとしています...
The MessageParam has requested to travel <BR/>From <MessageParam name="0" desc="city code"/> to <MessageParam name="1" desc="city code"/> on <MessageParam name="2" desc="date"/> at <MessageParam name="3" desc="time"/>.
出力が
The MessageParam has requested to travel <BR/>From <XXYY1 name="0" desc="city code"/> to <XXYY2 name="1" desc="city code"/> on <XXYY3 name="2" desc="date"/> at <XXYY4 name="3" desc="time"/>.
これが私のコードです
private void ProcessString()
{
String text = "The Traveler has requested to travel <BR/>From <MessageParam name=\"0\" desc=\"city code\"/> to <MessageParam name=\"1\" desc=\"city code\"/> on <MessageParam name=\"2\" desc=\"date\"/> at <MessageParam name=\"3\" desc=\"time\"/>.";
int Counter = 0;
StringBuffer outString = new StringBuffer();
Pattern pattern = Pattern.compile("(<MessageParam.*?>)");
Matcher matcher = pattern.matcher(text);
while (matcher.find())
{
Counter++;
String sReplacer = new StringBuffer("XXYY").append(Counter).toString();
matcher.appendReplacement(outString, sReplacer);
}
matcher.appendTail(outString);
System.out.println(outString.toString());
}
私が得ている出力は
The MessageParam has requested to travel <BR/> From XXYY1 to XXYY2 on XXYY3 at XXYY4.
私の正規表現が正しくないことは確かです。私は正規表現が苦手なので、何がうまくいかないのかわかりません。