php - jQueryはphpからjson形式で結果を取得します

Question

$.postPHPから結果を取り戻すにはどうすればよいですか？

$.post("sql/customer_save.php",{ what: "edit",customer_no: $customer_no});

phpが返信します

echo json_encode(array("customer_id"=>$customer_id,"customer_no"=>$customer_no));

結果を取り戻すには、$。postに何を置く必要がありますか？

Answer 1

$.post("sql/customer_save.php",{ what: "edit",customer_no: $customer_no},function(resp)
{
   //resp is your response
   //You can try
    console.log(resp);
    console.log(resp["customer_id"]); //get the value of customer_id
    console.log(resp["customer_no"]); //get the value of customer_no
},"json");

また

使用することもできます

 $.post("sql/customer_save.php",{ what: "edit",customer_no: $customer_no},function(resp)
    {
       //resp is your response
       //You can try
        var data = $.parseJSON(resp);
        console.log(data);
        console.log(data["customer_id"]); //get the value of customer_id
        console.log(data["customer_no"]); //get the value of customer_no
    });