php - Generate drop-down list input with values from DB table

Question

I am trying to generate a drop-down list with values from a MySQL table using Laravel. The table is simple, two columns - id and category.

The following will retrieve all of the records (categories) but returns an object rather than an array, which is what I need for the drop-down code -

$categories = Category::all();

The code for the drop-down is:

{{ Form::select('category', $categories, $post->category_id) }}

Ideas?

UPDATE

bgallagh3r suggested using a foreach loop to convert each category to an array. Their code got me close but generated a bunch of funky nested optgrouptags. I was able to get it down to just one optgroup but that is one too many..

$categories = Category::all();
foreach ($categories as $cat)
{
    $category = $cat->to_array();
    $id = $category['id'];
    $value = $category['category'];
    $cats[] = array($id => $value);
}

And then, in the form:

{{ Form::select('categories', $categories)}}

I end up with this HTML:

    <select name="categories">
    <optgroup label="0">
    <option value="1">Department News</option>
    </optgroup>
    <optgroup label="1">
    <option value="2">General</option>
    </optgroup>
   ...
    </select>

score 30 · Accepted Answer

You can try the 'lists' function:

$categories = Category::lists('category', 'id');

(Only for Laravel 3) Or even leave out the 'id' parameter, as it will default to the Model key, see http://laravel.com/api/source-class-Laravel.Database.Query.html#596

$categories = Category::lists('category');

(For Laravel 4, you do need the second param, see http://laravel.com/api/source-class-Illuminate.Database.Query.Builder.html#1034-1063)

score 4 · Accepted Answer

Depending on if you are using Eloquent for your models Category will return an array of objects, you need to convert the objects to arrays before passing them to the Form class.

foreach (Category::all() as $cat)
{
    $categories[] = array($cat->id => $cat->category);
}
{{ Form::select('categories', $categories)}}

score 3 · Accepted Answer

In Laravel 4, you can easily try like the following

//Query category and pass it  to the view that you want to show your category
$category = Category::lists('category_name', 'category_id');

In your view just add {{ Form::select('category', $category) }}. The result will be what you want, like the following

<select name="category">
        <option value="category_id">category_name</option>
</select>

score 1 · Accepted Answer

How about this ?

foreach (Category::all() as $cat)
{
    $categories[$cat->id] = $cat->category;
}
{{ Form::select('categories', $categories)}}

score 1 · Accepted Answer

Just tweeking bgallagh3r's code a little the following will work:

foreach (Category::all() as $cat)
{
    $categories[$cat->id] = $cat->category);
}
{{ Form::select('categories', $categories)}}

...although I prefer (In L4):

foreach (Category::select('id', 'category')->orderBy('id','asc')->get() as $cat)
{
  $categories[$cat->id] = $cat->category;
}
{{ Form::select('categories', $categories)}}

score 1 · Accepted Answer

For Laravel 5.3.x

In Controller

$categories = Category::pluck('name', 'id');

In View

{{ Form::select('categories', $categories)}}

score 0 · Accepted Answer

for laravel 5.2

in controller

$mechanics = User::where('role_id','3')->lists('name', 'id');

in view

{{   Form::select('mechanic_id', 
    [''=>'please select'] + $mechanics->toArray(), $order->mechanic_id , 
     array('id' =>'material-select2','class' => 'form-control'))  }}

php - Generate drop-down list input with values from DB table

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