0 
SELECT

    rates_Calendar.date,
    subQuery.name,
    COALESCE(subQuery.amount,0) as amount,
    subQuery.reference,
    subQuery.property


FROM
    rates_Calendar
    LEFT JOIN (
                SELECT
                    rates_Booking.date,
                    unit.unit,
                    unit.abbreviation as name,
                    rates_Booking.amount,
                    rates_Booking.bookingReference AS reference,
                    property.property


                FROM
                    rates_Booking

                    LEFT JOIN booking ON booking.reference = rates_Booking.bookingReference

                    LEFT JOIN unit ON booking.apartment = unit.unit

                    LEFT JOIN property ON property.property = unit.property

                    # unit to apartments
                    LEFT JOIN apartments ON (apartments.unit = unit.unit)
                    LEFT JOIN apartmentTypes ON (apartmentTypes.id = apartments.apartmentTypeId)

                WHERE
                    rates_Booking.date BETWEEN @startDate AND @endDate
                    AND unit.unit = 221



                GROUP BY
                    property.area,
                    property.property,
                    apartmentTypes.id,
                    unit.unit,
                    rates_Booking.date

                ) AS subQuery ON subQuery.date = rates_Calendar.date


 WHERE
     rates_Calendar.date BETWEEN @startDate AND @endDate
 GROUP BY 
subQuery.reference,
subQuery.unit,
subQuery.apartmentTypeId,
subQuery.property,
subQuery.area,
    rates_Calendar.date

さて、明らかにこのクエリは、一致しない日付に対してNULLをもたらします。すべてのNULLをNONNULL値で更新する方法はありますか？

2013-01-01  unitA 138 1      property1
2013-01-02  unitA 138 1      property1
2013-01-03  unitA 138 1      property1
2013-01-04  NULL  0   NULL   NULL
2013-01-05  NULL  0   NULL   NULL

それぞれの列のNONNULLでNULLを更新する方法はありますか？

リンクから理解できるように、NULLSでrowGroupsを非表示にすることはできないため、これを試みています。NULL 行グループを非表示にするJasperReports

4

4 に答える 4

1

LEFT JOIN私はあなたがあなたと一緒にその時を望んでいないと思いますsubQuery。これを試して：

SELECT

    rates_Calendar.date,
    subQuery.name,
    COALESCE(subQuery.amount,0) as amount,
    subQuery.reference,
    subQuery.property


FROM
    rates_Calendar, (
                SELECT
                    rates_Booking.date,
                    unit.unit,
                    unit.abbreviation as name,
                    rates_Booking.amount,
                    rates_Booking.bookingReference AS reference,
                    property.property


                FROM
                    rates_Booking

                    LEFT JOIN booking ON booking.reference = rates_Booking.bookingReference

                    LEFT JOIN unit ON booking.apartment = unit.unit

                    LEFT JOIN property ON property.property = unit.property

                    # unit to apartments
                    LEFT JOIN apartments ON (apartments.unit = unit.unit)
                    LEFT JOIN apartmentTypes ON (apartmentTypes.id = apartments.apartmentTypeId)

                WHERE
                    rates_Booking.date BETWEEN @startDate AND @endDate
                    AND unit.unit = 221



                GROUP BY
                    property.area,
                    property.property,
                    apartmentTypes.id,
                    unit.unit,
                    rates_Booking.date

                ) AS subQuery


 WHERE
   rates_Calendar.date BETWEEN @startDate AND @endDate
于 2013-01-09T16:15:41.340 に答える
1

これは、あなたの望むことですか？

SELECT rates_Calendar.date, coalesce(subQuery.name, 'unitA'),
        COALESCE(subQuery.amount,0) as amount,
        coalesce(subQuery.reference, 1),
        coalesce(subQuery.property, 'property1')
. . .

または、次のような列から値を読み取りますか?

select rates_Calendar.date,
       coalesce(subquery.Name, max(SubQuery.name) over ()) as name,
       COALESCE(subQuery.amount,0) as amount,
       coalesce(subQuery.reference, max(subquery.reference) over ()) as reference,
       coalesce(subQuery.property, max(subquery.property) over ()) as property

これにより、列から最大値が取得され、それがデフォルトとして使用されます。

于 2013-01-09T16:32:23.090 に答える
0

IFNULL関数が必要かもしれませんか？

select ifnull(some_field, 'default_value') from mytable
于 2013-01-09T16:13:33.737 に答える
0

CROSS JOIN ON rates_Calendar と unit テーブルを使用し、これら 2 つのテーブルのサブクエリを結合することで、これを行うことができました。

于 2013-01-21T12:59:13.743 に答える