linux - Count value in shell script

Question

I need help , i have a file output.txt

ttl 128
ttl 128
ttl 128
ttl 128
ttl 1
ttl 128
ttl 255
ttl 1
ttl 64
ttl 128
ttl 128
ttl 1

i need count how many times appear the same value in the lines of the file. The final result must be something like this:

ttl 128 - 7 times
ttl 64 - 1 time
ttl 255 - 1 time
ttl 1 - 3 times

I hope you can help me. I'm trying to use grep command.

Thanks a lot

score 4 · Accepted Answer

あなたはそれをuniqとで行うことができますsort：

<output.txt sort -V | uniq -c

出力：

3 ttl 1
1 ttl 64
7 ttl 128
1 ttl 255

score 3 · Accepted Answer

このジョブには sort 、 uniq で十分です。ただし、問題の説明と同じ出力形式を取得するには、この awk 行を試してください

awk '{a[$0]++}END{for(x in a){t=a[x]>1?"times":"time";print x " - "a[x],t}} file

例えば

出力は次のとおりです。

ttl 1 - 3  times
ttl 64 - 1 time
ttl 128 - 7  times
ttl 255 - 1 time

:)

score 0 · Accepted Answer

You can use the sort command to sort your file and uniq to make it unique and count the occurrences:

 sort output.txt | uniq -c

Note: Only 'problem' is that the counts are in front of each occurrence and in your example after it.

3 に答える 3