私の質問はとても簡単です。私がここに書いたコードは、ウェブページに全く出力を生成しません。私は一日中それに取り組んできましたが、私が見逃しているのは非常に単純なことだと確信しています。だから私はあなたの気さくな新鮮な目にアピールしています！これがうまくいかない理由を誰かが見つけられたら、とても感謝しています。
前提：
これは、次の条件を持つ意思決定ツリーのオンライン調査です。ユーザーがすでに調査を開始している場合、データベースでそれらを見つけ、最後に回答された質問を見つけて、次の質問を表示します。ただし、開始していない場合は、最初の質問が表示されます。
すべてのアンケートの質問は、デシジョン ツリー ロジックと同様にデータベースにも保持されます (たとえば、ユーザーが質問 1 に対してオプション 2 を選択した場合、質問は 2 ではなく質問 3 に送られます)。
現時点では、関連情報をデータベースから直接更新しており、ウェブサイトで自動化していないと仮定してください。
ありがとう ：）
PHP:
<?php
//Find the latest question reached by the user for display on the page
$sql = mysql_query("SELECT QuestionNumberReached FROM User WHERE EmailAddress = '***'");
$sqlCount = mysql_num_rows($sql);
if ($sqlCount > 0) {
while ($row = mysql_fetch_array($sql)) {
$QuestionNumberReached = $row["QuestionNumberReached"];
}
}
?>
<?php
//Find the last question answered by the user from the database
$StartedQuery = mysql_query("SELECT LastQuestionAnswered FROM User WHERE EmailAddress = '***'");
//Count the number of rows that the query produces
$StartedQueryCount = mysql_num_rows($StartedQuery);
//If data is found, whether it be a number or null, define the value
if ($StartedQueryCount > 0) {
while ($row = mysql_fetch_array($sql)) {
$LastQuestionAnswered = $row["LastQuestionAnswered"];
//If the field has a value and is not null, find the next question from the database
if (!empty($LastQuestionAnswered)) {
//Find the User's ID and the ID of the last question answered
$sqlA = mysql_query("SELECT PKID, LastQuestionAnswered FROM User WHERE EmailAddress = '***'");
//If the operation produces an error, output an error message
if (!$sqlA) {
die('Invalid query for SQLA: ' . mysql_error());
}
//Count the number of rows output
$sqlACount = mysql_num_rows($sqlA);
//If rows exist, define the values
if ($sqlACount > 0) {
while ($row = mysql_fetch_array($sqlA)) {
$sqlAPKID = $row["PKID"];
$sqlALastQuestionAnswered = $row["LastQuestionAnswered"];
}
}
//Find the answer given by the user to the last answered question
$sqlB = mysql_query("SELECT Answer FROM Responses WHERE User = $sqlAPKID");
//If the operation produces an error, output an error message
if (!$sqlB) {
die('Invalid query for SQLB: ' . mysql_error());
}
//Count the number of rows output
$sqlBCount = mysql_num_rows($sqlB);
//If rows exist, define the values
if ($sqlBCount > 0) {
while ($row = mysql_fetch_array($sqlB)) {
$sqlBAnswer = $row["Answer"];
}
}
//Find the number of the next question to be answered based on the user's previous answer and the question they answered
$sqlC = mysql_query("SELECT NextQuestion FROM Answers WHERE QuestionNumber = $sqlALastQuestionAnswered AND PKID = $sqlBAnswer");
//If the operation produces an error, output an error message
if (!$sqlC) {
die('Invalid query for SQLC: ' . mysql_error());
}
//Count the number of rows output
$sqlCCount = mysql_num_rows($sqlC);
//If rows exist, define the values
if ($sqlCCount > 0) {
while ($row = mysql_fetch_array($sqlC)) {
$sqlCNextQuestion = $row["NextQuestion"];
}
}
//Find the question text pertaining to the ID of the next question that needs to be answered
$sqlD = mysql_query("SELECT QuestionText FROM Questions WHERE PKID = $sqlCNextQuestion");
//If the operation produces an error, output an error message
if (!$sqlD) {
die('Invalid query for SQLD: ' . mysql_error());
}
//Count the number of rows output
$sqlDCount = mysql_num_rows($sqlD);
//If rows exist, define the values
if ($sqlDCount > 0) {
while ($row = mysql_fetch_array($sqlD)) {
$SurveyStartedQuestionText = $row["QuestionText"];
}
}
//Set a string of information that will show the question number and question text as appropriate
$ToDisplay = '' . $QuestionNumberReached . ': ' . $SurveyStartedQuestionText . '<br /><br />Answer Text Here';
//If the value for QuestionNumberReached is null, the user has not started the survey
} else if (empty($LastQuestionAnswered)) {
//Find the question text of the first question in the survey
$sql3 = mysql_query("SELECT QuestionText FROM Questions WHERE PKID IN (SELECT FirstQuestion FROM Batch WHERE BatchNumber IN (SELECT BatchNumber FROM User WHERE EmailAddress = '***'))");
//Count the number of rows output
$sql3Count = mysql_num_rows($sql3);
//If rows exist, define the values
if ($sql3Count > 0) {
while ($row = mysql_fetch_array($sql3)) {
$SurveyNotStartedQuestionText = $row["QuestionText"];
}
}
//Set a string of information that will show the question number and question text as appropriate
$ToDisplay = '' . $QuestionNumberReached . ': ' . $SurveyNotStartedQuestionText . '<br /><br />Answer Text Here';
}
}
}
?>
HTML:
<body>
<?php
// Display the concatenated information that has been previously defined
echo $ToDisplay;
?>
</body>