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def open_marks():
    N = (int(input('how many students? '))* 5)
    students = []
    for line in open('marks.txt').readlines():
       datafile = (line.strip().split('\t')[0].split(','))  
       for n in datafile:
          students.append(int(n))
    students=students[:N]
    return students
def open_marks1():
    students = open_marks()
    students1=students[0::5]#set to return only the first(lowest) marks drawn
    return students1
def open_marks2():
    students = open_marks()
    students2=students[1::5]#set to return only the second marks drawn
    return students2
def open_marks3():
    students = open_marks()
    students3=students[2::5]#set to return only the third marks drawn
    return students3
def open_marks4():
    students = open_marks()
    students4=students[3::5]#set to return only the fourth marks drawn
    return students4
def open_marks5():
    students = open_marks()
    students5=students[4::5]#set to return only the fifth(highest) marks drawn
    return students5


def count_ranges_one():

    students1 = open_marks1()
    print('first number: ',students1)
    range_counts1 = [0] * 12
    for num in students1[:]:#change number to select number of draws
        which_range=int(num//5)
        range_counts1[which_range] = range_counts1[which_range] + 1
    return range_counts1
def count_ranges_two():
    students2 = open_marks2()
    print('second number: ',students2)
    range_counts2 = [0] * 12
    for num in students2[:]:#change number to select number of draws
        which_range=int(num//5)
        range_counts2[which_range] = range_counts2[which_range] + 1
    return range_counts2
def count_ranges_three():
    students3 = open_marks3()
    print('third number: ',students3)
    range_counts3 = [0] * 12
    for num in students3[:]:#change number to select number of draws
        which_range=int(num//5)
        range_counts3[which_range] = range_counts3[which_range] + 1
    return range_counts3
def count_ranges_four():
    students4 = open_marks4()
    print('fourth number: ',students4)
    range_counts4 = [0] * 12
    for num in students4[:]:#change number to select number of draws
        which_range=int(num//5)
        range_counts4[which_range] = range_counts4[which_range] + 1
    return range_counts4
def count_ranges_five():
    students5 = open_marks5()
    print('fifth number: ',students5)
    range_counts5 = [0] * 12
    for num in students5[:]:#change number to select number of draws
        which_range=int(num//5)
        range_counts5[which_range] = range_counts5[which_range] + 1
    return range_counts5

7,5,10,25,32 9,15,25,39,18 などの形式の生徒のマークを含むテキスト ファイルがあります。上記は、位置 (1,2,3,4、または5) そして、マークの分布を表示するために「ヒストグラムを作成」するルーチンがあります。私が書いたことはひどく不器用で繰り返しですが、質問ごとのマークとしてグループ化されたデータと、ヒストグラムの範囲ごとの数を提供するループ関数を理解できません。誰かがロジックを手伝ってくれませんか。

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2

関数に引数を渡すことができることをご存知ですか? 5 つのopen_marks[1-5]機能は次のように一般化できます。

def open_marks_for_student(n):
    students = open_marks()
    return students[n-1::5]

たとえば 3 を関数に渡すと、古い open_marks3 関数と同じ結果が得られます。

open_marks_for_student(3)

関数にも同じ原則を適用できますcount_ranges。一般化された関数を記述し、マークを引数として渡すだけです。

def count_ranges(marks):
    range_counts = [0] * 12
    for num in marks[:]: #change number to select number of draws
        which_range=int(num//5)
        range_counts[which_range] = range_counts1[which_range] + 1
    return range_counts

次のように使用します。

def get_range_counts():
    range_counts = []
    student_nums = [1,2,3,4,5] #or range(1,6)
    for n in student_nums:
        marks = open_marks_for_student(n)
        range_counts.append(count_ranges(marks)) #create histogram, append to list
    return range_counts

marks学生ごとに 1 回ではなく 1 回だけマーク ファイルを開く、ループ内のスライスを削除するなど、いくつかの最適化を行うことができますcount_ranges。ループ) ですが、始めるにはこれで十分です。

于 2013-01-17T08:31:42.217 に答える