1

私の英語で申し訳ありません。私の質問が正しいかどうかわかりません。

私は配列を持っています：

Array
(
    [0] => Array
    (

        [date] => 2013-01-22
        [id] => 1
        [views] => 33286

    )

   [1] => Array
    (

        [date] => 2013-01-23
        [id] => 1
        [views] => 33223

    )


[2] => Array
    (

        [date] => 2013-01-22
        [id] => 2
        [views] => 33223

    )

 [3] => Array
    (

        [date] => 2013-01-23
        [id] => 2
        [views] => 33223

    )
)

ご覧のとおり、ID 1 と 2 には 2 日間 (2013 年 1 月 22 日と 2013 年 1 月 23 日) のビューがあります。

id     22-01-2013    23-01-2013
1        33286         33223
2        33223         33223

助けてくれてありがとう！

4

2 に答える 2

2

I doubt your end goal is to write out a table of values. But in case it is, here's some code that would do that.

<?php

$a = array(
    array('date'=>'2013-01-22', 'id'=>1, 'views'=>33286),
    array('date'=>'2013-01-23', 'id'=>1, 'views'=>33223),
    array('date'=>'2013-01-22', 'id'=>2, 'views'=>33223),
    array('date'=>'2013-01-23', 'id'=>2, 'views'=>33223),
);

$table = array();
$cols = array();
foreach ($a as $item)
{
   $date = date('d-m-Y', strtotime($item['date']));
   $table[$item['id']][$date] = $item['views'];
   $cols[$date] = 1;
}
$cols = array_keys($cols);

header('Content-type: text/plain');
echo("id\t" . implode("\t", $cols) . "\r");
foreach ($table as $rowName=>$row)
{
   echo("$rowName\t");
   foreach ($cols as $colName)
   {
      echo(@$row[$colName] . "\t");
   }
   echo("\r");
}

P.S. Just so you know, Stack Overflow isn't meant to be a place where we write code for you. I'm just in the mood to write code :-)

P.P.S. To the real PHP experts here, I'd love to know what optimizations should be made to this code :-)

于 2013-01-22T04:14:04.907 に答える
0

日付のフォーマット については、マニュアルを参照してください。

foreach ($yourarray as $key => $value){
    $yourarray[$key]['date'] = date("d-m-Y",strtotime($value['date']));
}

他の形式を上書きしてもかまわないと思います。

于 2013-01-22T04:03:59.607 に答える