linux - Windows バッチ スクリプトを Linux シェル スクリプトに変換する

Question

次の Windows バッチ スクリプト (.bat ファイル) があります。これをLinuxシェルスクリプトに変換したいと思います。助けてください...

@echo off
setlocal
for /f "tokens=2-7 delims=_.-" %%A in ('dir /B TACOS_*') do (
  setlocal enabledelayedexpansion
  call :getmonth %%B
  ren TACOS*_*%%A-%%B-%%C*_*%%D-%%E-%%F_UTC.csv TACOS_%%A!mon!%%C_%%D%%E%%F.csv
  endlocal
)

:getmonth
if "%1" equ "Jan" set mon=01
if "%1" equ "Feb" set mon=02
if "%1" equ "Mar" set mon=03
if "%1" equ "Apr" set mon=04
if "%1" equ "May" set mon=05
if "%1" equ "Jun" set mon=06
if "%1" equ "Jul" set mon=07
if "%1" equ "Aug" set mon=08
if "%1" equ "Sep" set mon=09
if "%1" equ "Oct" set mon=10
if "%1" equ "Nov" set mon=11
if "%1" equ "Dec" set mon=12
goto :eof
endlocal

これが私がこれまでに試したことです：

#!/bin/bash
set +v

for -f "tokens=2-7 delims=_.- A in ('Is-I -B TACOS_*'); do (
    getmonth B
    mv -iv TACOS*_*A-B-C*_*D-E-F_AST.csv TACOS_A!mon!C_DEF.csv
)


:getmonth
if "$1" equ "Jan" then mon=01
if "$1" equ "Feb" then mon=02
if "$1" equ "Mar" then mon=03
if "$1" equ "Apr" then mon=04
if "$1" equ "May" then mon=05
if "$1" equ "Jun" then mon=06
if "$1" equ "Jul" then mon=07
if "$1" equ "Aug" then mon=08
if "$1" equ "Sep" then mon=09
if "$1" equ "Oct" then mon=10
if "$1" equ "Nov" then mon=11
if "$1" equ "Dec" then mon=12
goto :eof

---

これが私がこれまでに試したことです

#!/bin/bash
set +v

for -f "tokens=2-7 delims=_.- A in ('Is-I -B TACOS_*'); do (
    getmonth B
    mv -iv TACOS*_*A-B-C*_*D-E-F_AST.csv TACOS_A!mon!C_DEF.csv
)


:getmonth
if "$1" equ "Jan" then mon=01
if "$1" equ "Feb" then mon=02
if "$1" equ "Mar" then mon=03
if "$1" equ "Apr" then mon=04
if "$1" equ "May" then mon=05
if "$1" equ "Jun" then mon=06
if "$1" equ "Jul" then mon=07
if "$1" equ "Aug" then mon=08
if "$1" equ "Sep" then mon=09
if "$1" equ "Oct" then mon=10
if "$1" equ "Nov" then mon=11
if "$1" equ "Dec" then mon=12
goto :eof