0

だから私は小さなテキストアドベンチャーで作っているお店の機能を持っています。コードは次のとおりです。

def shop():
global p #prompt for raw_input
global gold
global arrows

print"""
You enter the small shop and the man at the counter asks "How can I help?"
"""

print"""
"What would you like to buy?" He asks
You look up at the list of items
Copper Axe - 50G
Copper Sword - 50G
Wooden Bow - 30G
Copper Arrows (20) - 20G
Iron Axe - 100G
Iron Sword - 100G
Iron Arrows (20) - 40G
Steel Axe - 200G
Steel Sword - 200G
Steel Arrows (20) - 80G

or type 'exit' to exit the store
    """
print"You have:"
print inv

op = raw_input(p)

if op == "copper axe" or "Copper axe" or "Copper Axe" or "copper Axe":
    if gold < 50:
        print"You do not have enough gold"
        shop()
    else:
        gold = gold - 50
        inv.append("Copper Axe")
        shop()
if op == "copper sword" or "copper Sword" or "Copper sword" or "Copper Sword":
    if gold < 50:
        print"You do not have enough gold"
        shop()
    else:
        gold = gold - 50
        inv.append("Copper Sword")
        shop()
elif op == "Wooden bow" or "wooden bow" or "Wooden Bow" or "wooden Bow":
    if gold < 30:
        print"You do not have enough gold"
        shop()
    else:
        gold = gold - 30
        inv.append("Wooden Bow")
        if arrows < 10:
            print"You should probably buy some arrows"
            shop()
elif op == "Copper Arrows" or "copper arrows" or "Copper arrows" or "copper Arrows":
    if gold < 20:
        print"You do not have enough gold"
        shop()
    else:
        gold = gold - 20
        arrows = arrows + 20
        inv.append("Copper Arrows: %p" % arrows)
        shop()
elif op == "iron axe" or "Iron axe" or "Iron Axe" or "iron Axe":
    if gold < 100:
        print"You do not have enough gold"
        shop()
    else:
        gold = gold - 100
        inv.append("Iron Axe")
        shop()
elif op == "iron sword" or "Iron Sword" or "Iron sword" or "iron Sword":
    if gold < 100:
        print"You do not have enough gold"
        shop()
    else:
        gold = gold - 100
        inv.append("Iron Sword")
        shop()
elif op == "iron arrows" or "Iron arrows" or "Iron Arrows" or "iron Arrows":
    if gold < 40:
        print"You do not have enough gold"
        shop()
    else:
        gold = gold - 40
        iarrows = iarrows + 20
        inv.append("Iron arrows %a" % iarrows)
        shop()
elif op == "Steel Axe" or "steel axe" or "Steel axe" or "steel Axe":
    if gold < 200:
        print"You do not have enough gold"
        shop()
    else:
        gold = gold - 200
        inv.append("Steel Axe")
        shop()
elif op == "Steel Sword" or "steel sword" or "Steel sword" or "steel Sword":
    if gold < 200:
        print"You do not have enough gold"
        shop()
    else:
        gold = gold - 200
        inv.append("Steel Sword")
        shop()
elif op == "Steel Arrows" or "steel arrows" or "Steel arrows" or "steel Arrows":
    if gold < 80:
        print"You do not have enough gold"
        shop()
    else:
        gold = gold - 80
        sarrows = sarrows + 20
        inv.append("Steel Arrows - %a" % sarrows)
elif op == "exit" or "Exit":
    menu()
else:
    synerr() #syntax error function

基本的に、生の入力が何であれ、実行するたびに、銅の斧として返されます。このような：

You enter the small shop and the man at the counter asks "How can I help?"


"What would you like to buy?" He asks
You look up at the list of items
Copper Axe - 50G
Copper Sword - 50G
Wooden Bow - 30G
Copper Arrows (20) - 20G
Iron Axe - 100G
Iron Sword - 100G
Iron Arrows (20) - 40G
Steel Axe - 200G
Steel Sword - 200G
Steel Arrows (20) - 80G

or type 'exit' to exit the store

You have:
[]
>>>fkjas;ldkf

You enter the small shop and the man at the counter asks "How can I help?"


"What would you like to buy?" He asks
You look up at the list of items
Copper Axe - 50G
Copper Sword - 50G
Wooden Bow - 30G
Copper Arrows (20) - 20G
Iron Axe - 100G
Iron Sword - 100G
Iron Arrows (20) - 40G
Steel Axe - 200G
Steel Sword - 200G
Steel Arrows (20) - 80G

or type 'exit' to exit the store

You have:
['Copper Axe']
>>>

それで、これを引き起こしている可能性があるものを誰かが知っていますか？

4

1 に答える 1

0

この式：

op == "copper axe" or "Copper axe" or "Copper Axe" or "copper Axe"

このように評価されます：

(op == "copper axe") or "Copper axe" or "Copper Axe" or "copper Axe"

これがあなたが望むものです：

op == "copper axe" or op == "Copper axe" or op == "Copper Axe" or op == "copper Axe"

ところで、これがショートカットで、小文字に変換します。

op.lower() == "copper axe"
于 2013-01-23T01:32:30.763 に答える