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こんにちは、ある日付範囲で既存の日を定義する必要があります。開始日から終了日までループして、ここのように使用するつもりはありませんhttp://www.w3schools.com/jsref/jsref_getday.asp 何らかの方法で計算することは可能ですか?

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2 に答える 2

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function getDays(earlierDate, laterDate) {
  var dayNames = ["Sunday","Monday","Tuesday","Wednesday","Thursday","Friday","Saturday"];
  var elapsedDays = (laterDate - earlierDate) / 1000 / 60 / 60 / 24;
  if (elapsedDays < 7) {
    var dayArray = [];
    for (i = 0; i <= elapsedDays; i++) {
        dayArray.push(dayNames[(earlierDate.getDay()+i) % 7]);
    }
    return dayArray;
  }
  return dayNames;
}

js コンソールでのテスト:

> getDays(new Date("03-01-2012"), new Date("03-01-2012"));
["Thursday"]
> getDays(new Date("03-01-2012"), new Date("03-05-2012"));
["Thursday", "Friday", "Saturday", "Sunday", "Monday"]
> getDays(new Date("03-01-2012"), new Date("03-05-2013"));
["Sunday", "Monday", "Tuesday", "Wednesday", "Thursday", "Friday", "Saturday"]
于 2013-01-24T08:52:10.490 に答える
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 var sevenDaysInMS = 604800000;
    if (new Date(dTo - dFrom).getTime() >= sevenDaysInMS) {
        $('.day_hid').attr(attrUnaviableDay, "true");
    } else {
        var dt = dFrom;
        do {
            var day = dt.getDay();
            ActivateDaySelector(day);
            dt.setDate(dt.getDate() + 1);
        } while (dt <= dTo);
    }

大丈夫だと思います。どう思いますか ？

于 2013-01-24T08:49:30.010 に答える