0

Androidの魔女にアプリがあり、写真を撮り、PHPを使用してサーバーにアップロードする必要があります。

最初は問題なくアップロードできましたが、今度は画像をアップロードするパスをサーバーに渡す必要があります。問題は、2 つの値を送信しようとすると発生します。

次のコードを使用しています。

private  void httpPostFileUpload(String fpath, String uPath){
        HttpURLConnection connection = null;
        DataOutputStream outputStream = null;
        DataInputStream inputStream = null;

        //Path where to upload
        String uploadPath = uPath;

        String pathToOurFile = fpath;
        Log.v("file path",fpath.toString());
        String urlServer = "http://leojg.alwaysdata.net/tests/androidConnect/handle_upload.php";

        String lineEnd = "\r\n";
        String twoHyphens = "--";
        String boundary =  "*****";
        String fname = "";

        int bytesRead, bytesAvailable, bufferSize;
        byte[] buffer;
        int maxBufferSize = 1*1024*1024;

        try
        {
            File f = new File(pathToOurFile);
            fname =  f.getName();

            FileInputStream fileInputStream = new FileInputStream(f);

            URL url = new URL(urlServer);
            connection = (HttpURLConnection) url.openConnection();

            // Allow Inputs & Outputs
            connection.setDoInput(true);
            connection.setDoOutput(true);
            connection.setUseCaches(false);

            // Enable POST method
            connection.setRequestMethod("POST");

            connection.setRequestProperty("Connection", "Keep-Alive");
            connection.setRequestProperty("Content-Type", "multipart/form-data;boundary="+boundary);

            outputStream = new DataOutputStream( connection.getOutputStream() );
            outputStream.writeBytes(twoHyphens + boundary + lineEnd);

            Log.d("path file", pathToOurFile);
            Log.d("path up", uploadPath);

        outputStream.writeBytes("Content-Disposition: form-data; name=\"uploadedfile\";filename=\"" + pathToOurFile + "\"" + lineEnd);
            outputStream.writeBytes(lineEnd);

            bytesAvailable = fileInputStream.available();
            bufferSize = Math.min(bytesAvailable, maxBufferSize);
            buffer = new byte[bufferSize];

            // Read file
            bytesRead = fileInputStream.read(buffer, 0, bufferSize);

            while (bytesRead > 0)
            {
                outputStream.write(buffer, 0, bufferSize);
                bytesAvailable = fileInputStream.available();
                bufferSize = Math.min(bytesAvailable, maxBufferSize);
                bytesRead = fileInputStream.read(buffer, 0, bufferSize);
            }

            outputStream.writeBytes(lineEnd);
            outputStream.writeBytes(twoHyphens + boundary + twoHyphens + lineEnd);

            // Responses from the server (code and message)
            int serverResponseCode = connection.getResponseCode();
            String serverResponseMessage = connection.getResponseMessage();

            Log.d("amanda", "upload async finished, server response : " + serverResponseMessage);

            fileInputStream.close();
            fileInputStream = null;
            outputStream.flush();
            outputStream.close();
            outputStream = null;
            f= null;



            parent.invokeJs("pictureUploadEnded('" + fname + "')");
            this.delete(fpath);

        }
            catch (Exception ex)
        {
                Log.d("amanda", "exception uploading image : " + ex.getMessage());
        }     
}

問題はこの行にあると確信しています

outputStream.writeBytes("Content-Disposition: form-data; name=\"uploadedfile\";filename=\"" + pathToOurFile + "\"" + lineEnd);

投稿本文を作成するものです。uploadPathをどこに添付すればよいかわかりません

4

1 に答える 1

1

次のクラスは私にとってうまくいきます：

import java.io.DataOutputStream;
import java.io.File;
import java.io.FileInputStream;
import java.io.IOException;
import java.io.InputStream;
import java.net.HttpURLConnection;
import java.net.MalformedURLException;
import java.net.URL;
import org.json.JSONException;
import org.json.JSONObject;
import org.json.JSONTokener;
import android.os.Environment;
import android.util.Log;

public class HttpPictureUpload implements Runnable {
private String TAG = "HTTPFILEUPLOAD";
private URL connectURL;
private FileInputStream fileInputStream = null;
private String pictureFileName;
private String myName;

public HttpPictureUpload(String urlString, String pictureFileNameString,
        String myNameString) {
    try {
        connectURL = new URL(urlString);

        pictureFileName = pictureFileNameString;
        myName = myNameString;

    } catch (Exception ex) {
        Log.i(TAG, "URL Malformatted");
    }
}

public void SendPictureNow() {

    Sending();
}

private void Sending() {
    int maxBufferSize = 1 * 1024*1024*1024;
    String lineEnd = "\r\n";
    String twoHyphens = "--";
    String boundary = "*****";

    try {

        fileInputStream = new FileInputStream(Environment
                .getExternalStorageDirectory().toString()
                + "/Picture/"
                + pictureFileName);

        Log.e(TAG, "Starting Http File Sending to URL");

        // Open a HTTP connection to the URL
        HttpURLConnection conn = (HttpURLConnection) connectURL
                .openConnection();
        conn.setChunkedStreamingMode(maxBufferSize);
        // conn.setchu

        // Allow Inputs
        conn.setDoInput(true);

        // Allow Outputs
        conn.setDoOutput(true);

        // Don't use a cached copy.
        conn.setUseCaches(false);

        // Use a post method.
        conn.setRequestMethod("POST");

        conn.setRequestProperty("Connection", "Keep-Alive");

        conn.setRequestProperty("Content-Type",
                "multipart/form-data;boundary=" + boundary);

        DataOutputStream dos = new DataOutputStream(conn.getOutputStream());

        // sending appid
        dos.writeBytes(twoHyphens + boundary + lineEnd);
        dos.writeBytes("Content-Disposition: form-data; name=\"my_name\""
                + lineEnd);
        dos.writeBytes(lineEnd);
        dos.writeBytes(myName);
        dos.writeBytes(lineEnd);
        dos.writeBytes(twoHyphens + boundary + lineEnd);


        dos.writeBytes("Content-Disposition: form-data; name=\"file\";filename=\""
                + System.currentTimeMillis() + "\"" + lineEnd);
        dos.writeBytes(lineEnd);

        int bytesAvailable = fileInputStream.available();

        byte[] buffer = new byte[bytesAvailable];

        int bytesRead = fileInputStream.read(buffer, 0, bytesAvailable);

        while (bytesRead > 0) {
            dos.write(buffer, 0, bytesAvailable);
            bytesAvailable = fileInputStream.available();
            bytesAvailable = Math.min(bytesAvailable, maxBufferSize);
            bytesRead = fileInputStream.read(buffer, 0, bytesAvailable);
        }
        dos.writeBytes(lineEnd);
        dos.writeBytes(twoHyphens + boundary + twoHyphens + lineEnd);

        fileInputStream.close();

        dos.flush();

        Log.e(TAG,
                "File Sent, Response: "
                        + String.valueOf(conn.getResponseCode()));

        InputStream is = conn.getInputStream();

        // retrieve the response from server
        int ch;

        StringBuffer b = new StringBuffer();

        while ((ch = is.read()) != -1) {
            b.append((char) ch);

        }

        String s = b.toString();

        Log.i("Response", s);
        dos.close();
    } catch (MalformedURLException ex) {
        Log.e(TAG, "URL error: " + ex.getMessage(), ex);
    }

    catch (IOException ioe) {
        Log.e(TAG, "IO error: " + ioe.getMessage(), ioe);
    }
}

@Override
public void run() {
    // TODO Auto-generated method stub
}
 }

上記のクラスを使用して、画像ファイルまたはその他のファイルと任意の文字列を送信できます。
上記を使用するには： 

HttpPictureUpload uploadPicture=new HttpPictureUpload("http://serverurl.com/webservice.php", "tux.png", "my name is john");
uploadPicture.SendPictureNow();
于 2013-02-06T11:45:05.870 に答える