| uploadedby | uploaddate |
Gracey Vinas | 2012-04-20 20:16:00
Gracey Vinas | 2012-04-20 20:25:00
Gracey Vinas | 2012-04-20 20:35:00
Gracey Vinas | 2012-04-20 20:39:00
Gracey Vinas | 2012-04-20 22:07:00
Gracey Vinas | 2012-04-21 00:04:00
Gracey Vinas | 2012-04-21 01:14:00
Gracey Vinas | 2012-04-23 17:56:00
Gracey Vinas | 2012-04-23 18:06:00
Gracey Vinas | 2012-04-23 18:21:00
Gracey Vinas | 2012-04-23 19:04:00
Gracey Vinas | 2012-04-23 19:11:00
Gracey Vinas | 2012-04-23 19:24:00
Gracey Vinas | 2012-04-23 20:08:00
Gracey Vinas | 2012-04-23 20:22:00
Gracey Vinas | 2012-04-23 21:00:00
Gracey Vinas | 2012-04-23 22:04:00
Gracey Vinas | 2012-04-23 22:17:00
Gracey Vinas | 2012-04-23 22:29:00
Gracey Vinas | 2012-04-23 23:02:00
Gracey Vinas | 2012-04-23 23:48:00
Gracey Vinas | 2012-04-24 00:23:00
Gracey Vinas | 2012-04-24 01:54:00
Gracey Vinas | 2012-04-24 17:13:00
Gracey Vinas | 2012-04-24 17:32:00
Gracey Vinas | 2012-04-24 17:38:00
Gracey Vinas | 2012-04-24 17:45:00
Gracey Vinas | 2012-04-24 17:54:00
msqlで日付ごとに各アップロードの平均経過時間を取得するにはどうすればよいですか。例(2012-04-20の各アップロードの平均経過時間は(行1と行2の時間差(9分)+行2と行3の時間差(10分)+行3と行の時間差4(4分)+行4と行5の時間差(92分)/4=平均経過時間は28.75分です。