0

これは私のSQLステートメントです：

SELECT repnr, DATEDIFF(day, MIN(start), MAX(start) +1) AS DaysTotal
FROM TBLstatus 
WHERE status IN (1, 2, 3, 4, 8, 11, 20, 7, 23)
GROUP BY repnr HAVING COUNT(*) = 2 AND MAX(Start) > GETDATE()-30

Select repnr as repnr, CONVERT(float, SUM(DATEDIFF(day, start, slut))) as extern
From TBLstatus 
where status IN (5, 15, 17)
group by repnr

最初のものはこのデータを返します：

repnr daystotal
1000  100
1001  90
1003  91

および2番目のステートメント：

repnr extern
900   100
901   102
1000  21
1003  23

私が欲しいのは、repnr（ID）が一致する場所で、toの値を引いて、次のようにすることです。

repnr result
1000  79
1003  68

MSSQLでこれを行うにはどうすればよいですか。

4

3 に答える 3

1 
SELECT q1.repnr, q1.daystotal - q2.extern as [result]
FROM
(
SELECT repnr, DATEDIFF(day, MIN(start), MAX(start) +1) AS DaysTotal
FROM TBLstatus 
WHERE status IN (1, 2, 3, 4, 8, 11, 20, 7, 23)
GROUP BY repnr HAVING COUNT(*) = 2 AND MAX(Start) > GETDATE()-30
)q1
INNER JOIN 
(
Select repnr as repnr, CONVERT(float, SUM(DATEDIFF(day, start, slut))) as extern
From TBLstatus 
where status IN (5, 15, 17)
group by repnr
)q2 ON q1.repnr = q2.repnr
于 2013-01-29T14:22:59.007 に答える
1

クエリをサブクエリとして設定し、キーに参加してください。

select repnr, DaysTotal - extern as result from (SELECT repnr, DATEDIFF(day, MIN(start), MAX(start) +1) AS DaysTotal
FROM TBLstatus 
WHERE status IN (1, 2, 3, 4, 8, 11, 20, 7, 23)
GROUP BY repnr HAVING COUNT(*) = 2 AND MAX(Start) > GETDATE()-30) a inner join (Select repnr as repnr, CONVERT(float, SUM(DATEDIFF(day, start, slut))) as extern
From TBLstatus 
where status IN (5, 15, 17)
group by repnr) b on a.repnr = b.repnr
于 2013-01-29T14:26:59.347 に答える
0 
SELECT a.repnr, ABS(A.daystotal - b.extern) AS result
FROM(
SELECT repnr, DATEDIFF(day, MIN(start), MAX(start) +1) AS DaysTotal
FROM TBLstatus 
WHERE status IN (1, 2, 3, 4, 8, 11, 20, 7, 23)
GROUP BY repnr HAVING COUNT(*) = 2 AND MAX(Start) > GETDATE()-30
)A
JOIN(
Select repnr as repnr, CONVERT(float, SUM(DATEDIFF(day, start, slut))) as extern
From TBLstatus 
where status IN (5, 15, 17)
group by repnr
)B
ON A.repnr = b.repnr
于 2013-01-29T14:24:04.317 に答える